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lisabon 2012 [21]

3 years ago

11

What is the hottest object on earth? And why is it the hottest object on earth?

2 answers:

s344n2d4d5 [400]3 years ago

5 0

Answer:

The hottest thing on earth is the man-made quark-gluon plasma that is generated at the LHC at CERN by colliding two lead nuclei together at 7 GeV /c2.

Explanation:

shepuryov [24]3 years ago

5 0

Answer:

i think the hottest object on earth is the inner core. the inner core is 5430 degrees.

hope this helps

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What is the mass of ca(oh)2 in 110. mL of 1.244 M ca(oh)2 solution

stealth61 [152]

<em>V= 110mL = 110cm³ = 0,11dm³</em>
<em>C = 1,244 mol/L = 1,244 mol/dm³</em>

C = n/V
n = 1,244×0,11
<u>n = 0,13684 moles</u>

<em>mCa(OH)₂ = 74 g/mol</em>

1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
<u>X = 10,12616g</u>

:)

7 0

3 years ago

Predict how many antacid tablets it would take to produce 120 mL of CO2 gas

Aleksandr [31]

It would take 8 antacid tablets to produce 120 mL of CO2 gas.

8 0

2 years ago

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

valentinak56 [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

3 0

2 years ago

PLS ANSWER FAST WILL GIVE BRAINLY!!!!

castortr0y [4]

False because the sugar is just changing it’s form

7 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST

snow_tiger [21]

Answer:

I think it's B

Explanation:

I might be wrong, but please tell me.

5 0

2 years ago