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lisabon 2012 [21]
3 years ago
11

What is the hottest object on earth? And why is it the hottest object on earth?

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
5 0

Answer:

The hottest thing on earth is the man-made quark-gluon plasma that is generated at the LHC at CERN by colliding two lead nuclei together at 7 GeV /c2.

Explanation:

shepuryov [24]3 years ago
5 0

Answer:

i think the hottest object on earth is the inner core. the inner core is 5430  degrees.

hope this helps

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DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction. 2 C6H5Cl + C2HOCl3 → C14H9Cl5 + H
Elena-2011 [213]

Answer:

1,070.41 grams of DDT will be formed .Explanation:

1) 2 C_6H_5Cl + C_2HOCl_3\rightarrow C_{14}H_9Cl_5 + H_2O

Moles of chlorobenzene = \frac{1197 g}{112.5 g/mol}=10.64 mol

According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :

\frac{1}{2}\times 10.64 mol=5.32 mole of chloral

2) Moles of chloral = \frac{456 g}{147.5 g/mol}=3.0915 mol

According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :

\frac{2}{1}\times 3.0915 mol=6.1830 mol of chloro benzene

As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.

According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :

\frac{1}{1}\times 3.0195 mol=3.0195 mol

Mass of 3.0195 moles of DTT :

3.0195 mol × 354.5 g/mol = 1,070.41 g

1,070.41 grams of DDT will be formed .

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If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
goldfiish [28.3K]
The balanced chemical reaction:

<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

<span>0.06 mol Cu ( 63.55 g Cu / 1 mol Cu ) = 3.81 g Cu excess</span>
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