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Alisiya [41]
2 years ago
11

PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE H

ELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE

Chemistry
2 answers:
vesna_86 [32]2 years ago
8 0

Answer:

A. 1.67×10^-24

Explanation:

antiseptic1488 [7]2 years ago
3 0

Answer:

AAAAAAAAAAAAAAAAAAAAAAAAA

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Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?
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Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
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