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Alisiya [41]
2 years ago
11

PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE H

ELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE SCIENCE HELP PLEASE PLEASE HELP SCIENCE

Chemistry
2 answers:
vesna_86 [32]2 years ago
8 0

Answer:

A. 1.67×10^-24

Explanation:

antiseptic1488 [7]2 years ago
3 0

Answer:

AAAAAAAAAAAAAAAAAAAAAAAAA

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25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?
Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

115 * 25 = 300*V_{2}

2875 = 300*V_{2}

V_{2} = \frac {2875}{300}

V_{2} = 9.58

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

5 0
2 years ago
Calculate the number of grams of Mg needed for this reaction to release enough energy to increase the temperature of 78 mL of wa
Vaselesa [24]

Answer:

We need 1.1 grams of Mg

Explanation:

Step 1: Data given

Volume of water = 78 mL

Initial temperature = 29 °C

Final temperature = 78 °C

The standard heats of formation

−285.8 kJ/mol H2O(l)

−924.54 kJ/mol Mg(OH)2(s)

Step 2: The equation

The heat is produced by the following reaction:

Mg(s)+2H2O(l)→Mg(OH)2(s)+H2(g)

Step 3: Calculate the mass of Mg needed

Using the standard heats of formation:

−285.8 kJ/mol H2O(l)

−924.54 kJ/mol Mg(OH)2(s)

Mg(s) + 2 H2O(l) → Mg(OH)2(s) + H2(g)

−924.54 kJ − (2 * −285.8 kJ) = −352.94 kJ/mol Mg

(4.184 J/g·°C) * (78 g) * (78 - 29)°C = 15991.248 J required

(15991.248 J) / (352940 J/mol Mg) * (24.3 g Mg/mol) = 1.1 g Mg

We need 1.1 grams of Mg

7 0
3 years ago
.If a 20kg bicycle at the bottom of a hill has speed of 25m/s, how high can the cart go up the hill?
frez [133]
Idk I’m sorry. I just need points lol
4 0
3 years ago
Solids, liquids, and gases are three common states of matter. Which of these states of matter can flow?
Mademuasel [1]
Liquid it would be liquid 


5 0
3 years ago
Read 2 more answers
Which best describes the data?
blondinia [14]

Answer:

The average?

Explanation:

8 0
3 years ago
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