Calculate the mass of aluminum in 500 g of Al(C2H3O2)3
1 answer:
Answer: 66.2 g
Explanation:
1) The ratio of Al in the molecule is 1 mol to 1 mol .
2) The mass of 1 mol of molecules of Al (CH2H3O2)3 is the molar mass of the compound.
3) You calculate the molar mass of the compound using the atomic masses of each atom, in this way:
Al: 27 g/mol
C: 2 * 3 * 12 g/mol = 72 g/mol
H: 3 * 3 * 1 g/mol = 9 g/mol
O: 2 * 3 * 16 g/mol = 96 g/mol
Molar mass = 27 g/mol + 72 g/mol + 9 g/mol + 96 g/mol = 204 g/mol
4) Set a proportion:
27 g/mol x
-------------------- = ----------
204 g/mol 500 g
5) Solve for x:
x = 500 g * 27 g/mol / 204 g/mol = 66.2 g
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Answer:
1000mg= 1g
1L= 1000 mL
160cm = 1600mm
1.4km= 1400m
109 g = 0.109kg
250m= 0.250 km
80cm= 0.8 m
75mL= 0.075L
5.6m= 560 cm
6.5g= 6500mg
170.4m= 17040 cm
564 Dg = 5640 g
58 dg = 5800 mg
600 L= 0.6 KL
0.0923Km= 92300 mm
Explanation:
1 mg = 1x10⁻³ g
1 g = 1000 mg
1 g = 10 dg
1 g = 1x10⁻³ kg
1 Dg = 10 g
1 dg = 100 mg
1 L = 1000 mL
1 L = 1x10⁻³ KL
1 mL = 1x10⁻³ L
1 km = 1000 m
1 km = 1x10⁶ mm
1 m = 1x10⁻³ km
1 cm = 1x10⁻² m
1 cm = 10 mm