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Gre4nikov [31]
3 years ago
6

Calculate the mass of aluminum in 500 g of Al(C2H3O2)3

Chemistry
1 answer:
Luden [163]3 years ago
5 0
Answer: 66.2 g

Explanation:

1) The ratio of Al in the molecule is  1 mol to 1 mol .

2) The mass of 1 mol of molecules of Al (CH2H3O2)3 is the molar mass of the compound.

3) You calculate the molar mass of the compound using the atomic masses of each atom, in this way:

Al: 27 g/mol
C: 2 * 3 * 12 g/mol = 72 g/mol
H: 3 * 3 * 1 g/mol = 9 g/mol
O: 2 * 3 * 16 g/mol = 96 g/mol

Molar mass = 27 g/mol + 72 g/mol + 9 g/mol + 96 g/mol = 204 g/mol

4) Set a proportion:

    27 g/mol                x
-------------------- =  ----------
   204 g/mol            500 g

5) Solve for x:

x = 500 g * 27 g/mol / 204 g/mol = 66.2 g
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The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

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This is a redox reaction, which <u>is a chemical reaction in which one or more electrons are transferred between the reagents</u>, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

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425.0 mL x \frac{1 L}{1000 mL} x  \frac{0.25 mol Cr(NO_{3})_{3}  }{1 L} x \frac{2 mol Cr  }{2 mol Cr(NO_{3})_{3} } x \frac{51.9961 g Cr}{1 mol Cr} = 5.52 g

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