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podryga [215]
3 years ago
8

A fruit bowl contains apples, oranges, and bananas. The radius of one of the oranges is 1.45 inches. What is the approximate vol

ume of the orange? Use 3.14 for .
Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

12.76 in³

Step-by-step explanation:

The volume of a sphere formula is V = (4/3)πr³.

Here we use 3.14 for π and 1.45 in for r.  We get:

V = (4/3)(3.14)(1.45 in)³ ≈ 12.76 in³

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Round 639,121 to the nearest ten thousand.
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640,121

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Pls help me! I will mark brainliest if you are correct
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I' would say A but C could be a possibility.

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I just can't do this
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You can, it's not as hard as you might think

simply multiply the speed by the fraction of time

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3 years ago
Step 3: Multiply by the scalar (1 over the determinant): Aâ’1 = a11 a12 a21 a22 a11 = a12 = a21 = a22 =
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3 years ago
A student has a 30% chance of receiving chocolate ice cream for dessert at lunch. A statistics class designs a simulation to app
Nadusha1986 [10]

The count of the sections the class should label as "Chocolate Ice Cream" is 3.

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

For the considered case, it is given that:

Probability of an student getting Chocolate Ice Cream for dessert at lunch =  30% = 0.3

The count of the sections the class should label as "Chocolate Ice Cream" should be such that spinner getting "Chocolate Ice Cream" as option should have the probability as 0.3

Let the count of the sections the class should label as "Chocolate Ice Cream"  be x

Then, as there are in total 10 sections in the spinner, and all sections are assumingly equally probable, thus, if the event E is:

E = event of getting "Chocolate Ice Cream" in the spinner ,

then as n(E) = x (as there are x sections with label "Chocolate Ice Cream")

and n(S) = total count of sections (size of sample space)  = 10

Thus, we get probability of event E as:

P(E) = \dfrac{n(E)}{n(S)} = \dfrac{x}{10}

This needs to be equal to 0.3, thus,

0.3 = \dfrac{x}{10}\\x = 3


Thus, the count of the sections the class should label as "Chocolate Ice Cream" is 3.

Learn more about probability here:

brainly.com/question/1210781

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2 years ago
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