What is the wavelength in nm of a light whose first order bright band forms a
1 answer:
Answer:
714 nm
Explanation:
Using the equation: nλ=d<em>sin</em>θ
where
n= order of maximum
λ= wavelength
d= distance between lines on diffraction grating
θ= angle
n is 1 because the problem states the light forms 1st order bright band
λ is unknown
d= or 0.0000014 (meters)
sin(30)= 0.5
so
(1)λ=(0.0000014)(0.5)
=0.000000714m or 714 nm
You might be interested in
Solution :
a).
This compound is known as sulfur trioxide.
The molecular shape of sulfur trioxide is trigonal planer.
And the bond angle is 120°.
b).
This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.
It is linear in shape.
The bond angle between them is 180°.
c).
This compound is known as the Dichloromethane.
The molecular shape of the compound is tetrahedral.
The bond angles is 120°
