Answer:
The answer to your question is Aluminum
Explanation:
Number of clues
1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.
For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.
2.- It makes three bonds to become stable, then we are looking for and element located in the third group like
Boron, Aluminum, Gallium, Indium, etc
Conclusion
The element that has both characteristics is Aluminum
1 - Chemistry is a branch of science focusing on elements, reactions, and chemicals.
2 - We study chemistry to learn more about these chemicals and elements and to discover new chemicals as well as to answer questions in life about reactions.
3 - Chemistry relates to our life in various ways, from the chemicals we inhale to the basic reactions in cooking and baking.
4 - The main branches of Chemistry are Physical, analytical, biochemistry, organic and inorganic chemistry.
Hope this helps!
Since an acidic salt solution is produced when a strong acid neutralizes a weak base, the pH of the salt solution formed when HCl is added to R2NH will be less than 7.
<h3>What is a neutralization reaction?</h3>
A neutralization reaction is the react ion between an acid and a base to form salt and water only.
Neutralization reactions can either produce a neutral solution, an acidic solution or an alkaline solution at equivalence point.
When a strong acid is added to a weak base, the pH of the salt solution formed will be less than 7.
Therefore, the pH of the salt solution formed when HCl is added to R2NH will be less than 7.
Learn more about pH at: brainly.com/question/940314
<h3>
Answer:</h3>
0.387 J/g°C
<h3>
Explanation:</h3>
- To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
- Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
- That is, Q = mcΔT
in our question we are given;
Mass of copper, m as 95.4 g
Initial temperature = 25 °C
Final temperature = 48 °C
Thus, change in temperature, ΔT = 23°C
Quantity of heat absorbed, Q as 849 J
We are required to calculate the specific heat capacity of copper
Rearranging the formula we get
c = Q ÷ mΔT
Therefore,
Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)
= 0.3869 J/g°C
= 0.387 J/g°C
Therefore, the specific heat capacity of copper is 0.387 J/g°C
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