45 cm^3 i think? not sure tbh sorry
Answer:
The richer source of calcium is fluorite.
Explanation:
Percentage of element in compound :
1. Dolomite is a carbonate of magnesium and calcium:
Given mass of dolomite = 7.81 g
Mass of calcium present in given mass of dolomite = 1.70 g
Percentage of calcium in Dolomite:
2. Fluorite is a mineral of calcium and fluorine:
Given mass of fluorite = 2.76 g
Mass of fluorine present in given mass of fluorite = 1.34 g
Percentage of fluorine in fluorite :
Percentage of calcium in fluorite = 100% - 48.55 % = 51.45%
Percentage of calcium in fluorite > Percentage of calcium in Dolomite
51.455 > 21.77%
So, the richer source of calcium is fluorite.
Answer:
High temperatures
Explanation:
NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)
As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).
As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).
<em>In terms of ΔG:</em>
<em>In order for the reaction to be thermodynamically favorable, ΔH has to be negative</em>, thus:
- The reaction is favorable if TΔS > ΔH.
The greater the temperature, the easier it would be for TΔS to be greater than ΔH.
Answer:
The globs rises due to convection.
Explanation:
Convection is when warmer parts move to the top and the cooler parts move to the bottom. Since the globs are going to be warmer, they rise to the top.
Hope this helps :D
Answer: The temperature of the gas is 132.25K and -140.75°C
Explanation:
Given that:
Volume of helium gas (V) = 18.5L
Temperature of helium gas (T) = ?
Pressure (P) = 0.85 atm
Number of moles (n) = 1.45 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T
15.725 atm•L = 0.1189 atm•L•K-1 x T
T = 15.725 atm•L / 0.1189 atm•L•K-1
T = 132.25K
Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273
So, T(in Celsius) = 132.25K - 273
= -140.75°C
Thus, the temperature of the gas is 132.25K and -140.75°C
