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3 years ago

The properties of a rectangular prism are listed below:

Physics

2 answers:

diamong [38]3 years ago

8 0

Answer:

mass = 960 g

Explanation:

The rectangular prism have a density, length , width and height. We are asked to calculate the mass of the rectangular prism from the data given above.

The density of an object measures the mass of the object to it volume. Mathematically, density is the mass of an object divided by it volume. It is represented as follows;

density = mass/volume

The density of the prism is known from the data given but the volume is not given . Base on the data given, one could compute volume of the rectangular prism.

volume of a rectangular prism = Length × width × height

length = 4cm

width = 2cm

height = 1cm

volume of a rectangular prism = 4 × 2 × 1

volume of a rectangular prism = 8cm³

Since the volume is known the mass can be computed from the density formula.

density = mass/volume

mass = density × volume

density = 120 g/cm³

volume = 8cm³

mass = 120 × 8

mass = 960 g

Mashcka [7]3 years ago

6 0

First calculate the volume of the rectangular prism by multiplying its length, width and height. The volume of the prism is 8 cm^3. Since density is known to be mass over volume, just multiply the given density with the volume. The mass of the prism then is 960 grams.

and Since density is the ratio of the substance's mass to its volume,
Density = Mass/Volume
Mass = Density*Volume

The volume of a rectangular prism is:
V = LWH = 4×2×1 = 8 cm³

Mass = (120 g/cm³)(8 cm³)
Mass = 960 grams

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What is a lever and mention its types

Grace [21]

Answer:

Three different types of levers exist, depending on where the input force, fulcrum, and load are. A class 1 lever has the fulcrum between the input force and load. A class 2 lever has the load between the fulcrum and input force. A class 3 lever is a lever that has the input force in between the fulcrum and the load.

Explanation:

3 0

3 years ago

1.A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two seconds. What is its acceleration?

FrozenT [24]

$\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}$

<h3>Provided:-</h3>

Initial velocity = 15 m/s
Final velocity = 10 m/s
Time taken = 2 s

Accleration of the particle....?

<h3>How to solve?</h3>

We will solve the above Question by using equations of motion that are:-

v = u + at
s = ut + 1/2 at²
v² = u² + 2as

Here,

v = Final velocity
u = Initial velocity
a = acceleration
t = time taken
s = distance travelled

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

━━━━━━━━━━━━━━━━━━━━

5 0

4 years ago

A body of mass 0.5kg is thrown vertically upwards from the ground with an initial velocity of 80.0m/s

Paul [167]

Answer:

1) 3.92 J

2) 1596.08 J

3) 16.3 s ??

Explanation:

Initial Potential energy PE = mgh = 0.5(9.8)(0) = 0 J

Initial Kinetic energy KE = ½mv² = ½(0.5)80² = 1600 J

PE = 0.5(9.8)(0.80) = 3.92 J

KE = 1600 - 3.92 = 1596.08 J

Question 3 is not clear

to the point 80 cm above the ground the flight time is only 0.01 s

The time when the mass strikes ground again will be twice the time gravity takes to reduce the initial velocity to zero

t = 2(80.0 / 9.8) = 16.3 s

would not 80 m above the ground be a much more interesting point to consider?

PE = 0.5(9.8)(80) = 392 J

KE = 1600 - 392 = 1208 J

v₈₀ = √(2(1280) /0.5) = 69.5 m/s

t₈₀ = h/v(avg) = 80 / (½(80 + 69.5)) = 1.07 s

7 0

3 years ago

Interestingly, there have been several studies using cadavers to determine the moment of inertia of human body parts by letting

loris [4]

Answer:

0.08735 kgm²

Explanation:

m = Mass of lower leg = 5 kg

L = Length of leg = 18 cm

g = Acceleration due to gravity = 9.81 m/s²

f = Frequency = 1.6 Hz

I = Moment of inertia

Time period is given by

$T=2\pi\sqrt{\dfrac{I}{mgL}}$

Also

$T=\dfrac{1}{f}$

So,

$I=\dfrac{mgL}{(2\pi f)^2}\\\Rightarrow I=\dfrac{5\times 9.81\times 0.18}{(2\pi 1.6)^2}\\\Rightarrow I=0.08735\ kgm^2$

The moment of inertia of the lower leg is 0.08735 kgm²

8 0

4 years ago

A nonconducting spherical shell, with an inner radius of 4 cm and an outer radius of 6 cm, has charge spread non uniformly throu

Aloiza [94]

In other words a infinitesimal segment dV caries the charge
dQ = ρ dV 

Let dV be a spherical shell between between r and (r + dr): 
dV = (4π/3)·( (r + dr)² - r³ ) 
= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) 
= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) 
drop higher order terms 
= 4·π·r²·dr 

To get total charge integrate over the whole volume of your object, i.e. 
from ri to ra: 
Q = ∫ dQ = ∫ ρ dV 
= ∫ri→ra { (b/r)·4·π·r² } dr 
= ∫ri→ra { 4·π·b·r } dr 
= 2·π·b·( ra² - ri² ) 

With given parameters: 
Q = 2·π · 3µC/m²·( (6cm)² - (4cm)² ) 
= 2·π · 3×10⁻⁶C/m²·( (6×10⁻²m)² - (4×10⁻²m)² ) 
= 3.77×10⁻⁸C 
= 37.7nC

6 0

4 years ago