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kow [346]
3 years ago
13

Energy from the Sun travels to Earth as ______. a. mechanical energy a. mechanical energy b. chemical energy c. radiant energy d

. combustion
Physics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

Radiant energy

Explanation:

Radiant energy is energy that travels by waves or particles, particularly electromagnetic radiation such as heat or x-rays.

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Which periodic element has 2 neutrons
DiKsa [7]
The answer would be: element helium
7 0
3 years ago
A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete
Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa   ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

Pa \ + \ \frac{1}{2} \  \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2

\frac{1}{2} \  \delta \ v^2_1 \ = P + \delta gy_2 -  \ \delta gy_1  - Pa

\frac{1}{2} \  \delta \ v^2_1 \ =  \delta g(y_2 -y_1 )+   ( P   - Pa )

v_1 \ =  \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+  2  ( P   - Pa )}{\delta}}

where;

Pa = atmospheric pressure = 101325 Pa

\delta = density of liquid = 900 kg/m³

v_1 = initial velocity = ???

g = 9.8 m/s²

y_1 = height of the hole from the buttom

y_2 = height of the liquid surface from the button

v_1 \ =  \sqrt{ \frac {2*900*9.8(7 -  0.5 )+  2  ( 200,000   - 101325 )}{900}}

v_1 = 18.62 \ m/s

Thus, the initial  velocity of the fluid jet  = 18.62 m/s

3 0
3 years ago
I need help on these 3 questions. <br> I need the original formula used and the givens
Dafna11 [192]

Answer:

sorry mate i dont know

Explanation:

sorry i just need points and i hope you get your answers

7 0
3 years ago
If a pitch vibrates at 880 cycles, the octave below would vibrate at ____ cycles. 220 440 660 1760
eduard

Answer:

If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.

Explanation:

Pitch of sound is defined as relative highest and the lowest point of sound. The pitch is dependent on frequency of vibration.

Octave is defined as a tone which is formed due to merging of two different tone. The resultant tone is merged so well that it sound like a single tone.

Thus, Number cycle in octave = \frac{number of cycles in a pitch}{2}

Number cycle in octave = \frac{880}{2}

Number cycle in octave = 440

Thus, If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.

7 0
3 years ago
Help me complete it. differentiate the types of collision
kolbaska11 [484]
Elastic
☑ occur when the colliding objects bounce off of each other
☑ hard or bouncy objects
☑ kinetic energy is conserved

Inelastic
☑ occur when two objects collide
☑ two objects colliding stick together
☑ kinetic energy is not conserved — some of the initial kinetic energy is converted into other types of energy (heat, sound, etc.)
4 0
3 years ago
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