Normal reaction force on the block while it is at rest on the inclined plane is given as

here we know that
m = 46 kg

now we will have

now the limiting friction or maximum value of static friction on the block will be given as


Above value is the maximum value of force at which block will not slide
Now the weight of the block which is parallel to inclined plane is given as

here we know that

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.
So here <u>friction force on the given block will be same as its component on weight which is 218.55 N</u>
Answer:
The small pebble
Explanation:
Since the potential energy, P.E lost equals kinetic energy, K.E gained,
P.E = K.E
P.E = mgh = K.E
So, K.E = mgh where g = acceleration due to gravity and h = height of drop
Since h and g are constant
K.E ∝ m
So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.
Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.
If the acceleration of a moving object is zero, the object remains at a constant speed (without friction)
It’s used in measuring distance from earth with other celestial object. Hope this helps mark brainest