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Anon25 [30]
3 years ago
10

PHYSICS QUESTION: specific heat capacity

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
1*10*1000=10000 energy= temp change*mass*specific heat capacity
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Objects 1 and 2 attract each other with a gravitational force
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What is the formula to find PE and KE ?
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PE stands for Potential Energy. It is the stored energy in an object due to its position with respect to some reference. It is expressed in Joules.

P.E = m * g * h    OR  P.E. = mgh

m - mass of the body
g - acceleration due to gravity
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K.E = 1/2 mv²    where m = mass of the body; v = velocity with which the body is moving.
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3 years ago
Snails crawl very slowly. If a garden snail crawls at 0.013 m/s north, how far will it travel in 60 seconds?
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7 0
3 years ago
A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh
andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by \frac{1}{2}QC where Q is the charge on it and C is its capacitance. The capacitance is defined, geometrically, as

\dfrac{\epsilon A}{d}

where \epsilon is a constant that is determined by the material between the plates, A is the area of the plates and d is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, C_1 at initial separation, d_1

C_1=\dfrac{\epsilon A}{d_1}

If separation is doubled, separation becomes d_2=2d_1. Then the capacitance becomes

C_2=\dfrac{\epsilon A}{d_2}

C_2=\dfrac{\epsilon A}{2d_1}

C_2=0.5\dfrac{\epsilon A}{d_1}

C_2=0.5C_1

Initial energy, E_1=\frac{1}{2}QC_1

Final energy, E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1

E_2=0.5\times\frac{1}{2}QC_1=0.5E_1

Hence, \frac{E_2}{E_1}=0.5

5 0
3 years ago
When temperature decreases but actual water vapor content remains the same, what happens to relative humidity?
ruslelena [56]

Answer:

d. Relative humidity increases.

Explanation:

The expression of relative humidity in terms of absolute humidity, absolute pressure and saturation pression at measured temperature is:

\phi = \frac{\omega \cdot P}{(0.622+\omega)\cdot P_{sat}}

When temperature decreases, the saturation pressure decreases also and, consequently, relative humidity increases. Therefore, the right answer is option D.

8 0
3 years ago
Read 2 more answers
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