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zheka24 [161]
4 years ago
12

What are the two most common minerals located in Earth's crust

Physics
2 answers:
algol [13]4 years ago
8 0
Quartz and Feldspar are the two common minerals in the earths crust

Quartz is hard white or colorless mineral consisting of silicon dioxide, found widely in igneous metamorphic, and sedimentary rocks. It is often colored by impurities.

Feldspar is an abundant rock froming mineral typically ocurring as colorless or pale colored crystals and consisting of alluminosilicates of potasium, sodium, and calcium
Bas_tet [7]4 years ago
6 0
The one most common mineral is the feldspar, which takes up 60 % of the weight, and the second most common is quartz. Both have silicon and oxygen in them.
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11. A wire made of silver has coefficient of linear expansion, 29x10-6/k and length of 10m. A square metal plate made of such si
Levart [38]

By using the coefficient of linear expansion, the increase in the length of the metal plate is by 0.015m and in the area is by 0.3074m^2.

The rate of change in length of a metal per degree change in temperature is known as the coefficient of linear expansion.

Given:

Coefficient of linear expansion, α = 29 x 10^-^6/k

Length, L1 = 10m

T1 = 25℃

T2 = 78℃

ΔT = 78 – 25 = 53℃

To find:

Change in length (ΔL) and area (ΔA) of metal plate = ?

Formula:

ΔL = α L1 ΔT

ΔA = A1 2 α ΔT

Calculations:

ΔL = 29 x 10^-^6 x 10 x 53

ΔL = 0.01537m

ΔA = 100 x 2 x 29 x 10^-^6 x 53

ΔA = 0.3074m^2

A2 = 100.3074m^2

Result:

The increase in the length and area is by 0.015m and 0.3074m^2 respectively.

Learn more about Coefficient of linear expansion of metals here:

brainly.com/question/14780533

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5 0
1 year ago
What is the chemical formula for dicarbon hexafluoride?
ExtremeBDS [4]

Answer:

I believe its D

Explanation:

6 0
4 years ago
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A pitcher claims he can throw a 0.146-kg baseball with as much momentum as a 2.70-g bullet moving with a speed of 1.50 ✕ 103 m/s
Nataly_w [17]

(a) The pitcher must throw the ball at 27.7 m/s

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is the object's velocity

Let's calculate the momentum of the bullet, which has a mass of

m = 2.70 g = 0.0027 kg

and a velocity of

v=1.50\cdot 10^3 m/s

Its momentum is:

p=mv=(0.0027 kg)(1.50\cdot 10^{3} m/s)=4.05 kg m/s

The pitcher must throw the baseball with this same momentum. The mass of the ball is

m = 0.146 kg

So the velocity of the ball must be

v=\frac{p}{m}=\frac{4.05 kg m/s}{0.146 kg}=27.7 m/s

So, the pitcher must throw the ball at 27.7 m/s.

(b) a. The bullet has greater kinetic energy

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where m is the mass of the object and v is its speed.

For the bullet, we have:

K=\frac{1}{2}(0.0027 kg)(1.50\cdot 10^3 m/s)^2=3037.5 J

For the ball:

K=\frac{1}{2}(0.146 kg)(27.7 m/s)^2=56.0 J

So, the bullet has greater kinetic energy.

6 0
3 years ago
Do you think radio waves and x-rays are types of light?
goblinko [34]

Answer:

yes, radio waves and x-rays are type of light.

6 0
3 years ago
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How to find the acceleration of a system?
natta225 [31]
The acceleration can be found by:
\frac{v}{t}
Where v= velocity and t= time
or
a  =  \frac{f}{m}
6 0
3 years ago
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