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3 years ago

What is the chemical formula for dicarbon hexafluoride?

Physics

2 answers:

cricket20 [7]3 years ago

8 0

Answer: it’s C

Explanation: di- 2 and hexa- 6

Carbon is first and has the prefix of di so it’s C2 and fluoride is last with the prefix hexa

ExtremeBDS [4]3 years ago

6 0

Answer:

I believe its D

Explanation:

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A mass of 0.8 kg is fixed at a vertical spring with an unknown spring constant. When spring is released from rest, it extends to

Delicious77 [7]

Answer:

1) k = 52 N/m

2) E = 1.0 J

3) ω = 8.1 rad/s

4) v = 1.4 m/s

Though asked for a velocity, we can only supply magnitude (speed) because we don't have enough information to determine direction.

If it happens to be the first time it is at y = - 10 cm after release, the velocity is upward.

Explanation:

Assuming the initial setup is after all transients are eliminated.

kx = mg

k = mg/x = 0.8(9.8) / 0.15

k = 52.26666.... ≈ 52 N/m

E = ½kA² = ½(52)(0.20²) = 1.045333... ≈ 1.0 J

ω = √(k/m) = √(52 / 0.8) = 8.0829... ≈ 8.1 rad/s

½mv² = ½kA² - ½kx²

v = √(k(A² - x²)/m) = √(52(0.20² - 0.10²)/0.8) = 1.39999... ≈ 1.4 m/s

4 0

2 years ago

A box with the mass of 15 kg is lifted to a shelf, how much force is needed?

viva [34]

The object has a mass of 15 kilograms. Therefore, it weighs 147 newtons on Earth, where gravitational acceleration is 9.8 meters per second per second. To counteract gravity, the acting force needs to be at least 147 newtons, It has to move 3 meters upward. When multiplying force by distance, the product comes to 441 joules, where joules are the standard unit of work.

5 0

2 years ago

A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What

Vikentia [17]

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

$a_{c} =\frac{v^{2} }{r}$

Where $a_{c}$ is the centripetal acceleration

$v$ is the velocity

and $r$ is the radius

From the given information

$v = 12 \ m/s$

and $r = 30 \ m$

Therefore,

$a_{c} =\frac{12^{2} }{30}$

$a_{c} =\frac{144 }{30}$

$a_{c} = 4.8\ m/s^{2}$

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

4 0

2 years ago

A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d

yawa3891 [41]

I think its true i dont kno for sure

4 0

2 years ago

The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C(mass 2.34×10−26kg) decays by the process known

Nookie1986 [14]

Answer:

2240.92365 m/s

Explanation:

$m_1$ = Mass of electron = $9.11\times 10^{−31}\ kg$

$v_1$ = Speed of electron = $5.7\times 10^7\ m/s$

$p_2$ = Neutrino has a momentum = $7.3\times 10^{-24}\ kg m/s$

M = total mass = $2.34\times 10^{-26}\ kg$

In the x axis as the momentum is conserved

$Mv_x=m_1v_1\\\Rightarrow v_x=\dfrac{m_1v_1}{M}\\\Rightarrow v_x=\dfrac{9.11\times 10^{−31}\times 5.7\times 10^7}{2.34\times 10^{-26}}\\\Rightarrow v_x=2219.10256\ m/s$

In the y axis

$Mv_y=p_2\\\Rightarrow v_y=\dfrac{p_2}{M}\\\Rightarrow v_y=\dfrac{7.3\times 10^{-24}}{2.34\times 10^{-26}}\\\Rightarrow v_y=311.96581\ m/s$

The resultant velocity is

$R=\sqrt{v_x^2+v_y^2}\\\Rightarrow R=\sqrt{2219.10256^2+311.96581^2}\\\Rightarrow R=2240.92365\ m/s$

The recoil speed of the nucleus is 2240.92365 m/s

3 0

3 years ago