Answer: D. it has been demonstrated to be without exception under certain stated conditions.
Explanation:
A <u>Law</u> is an affirmation (something established) based on repeated long-term observation of a phenomenon that has been studied and verified.
That is: A law is present in all known theories and therefore is considered universal. In addition, a law can not be refuted, nor changed, because its precepts have been proven through various studies.
<u>Unlike theory</u>, which is the set of rules and principles that describe and explain a particular phenomenon and <u>is subject to changes as new evidence emerges that gives meaning to it. </u>
Then, based on what is explained above, the law of universal gravitation is a statement that exists because it was rigorously tested and verified, therefore it can not be refuted.
Answer:
= 7.07 m
Explanation:
The Tarzan reaches bottom of swing after descending 2.5 m,
change in his potential energy equals his kinetic energy at bottom of swing
m g h = (1/2) m v² ,
hence speed v of Tarzan at bottom of swing is given as
v = ( 2 g h )1/2
= ( 2 × 9.8 × 2.5 )1/2
= 7 m/s
At the bottom of swing, if the vine breaks, then he is moving with horizontal velocity 7 m/s in gravitational field.
If vertical distance from ground to bottom of swing is 5 m, then time t for Tarzan to reach ground is given by
S = (1/2)g t2 or t = (2S/g)1/2
= ( 2 × 5 / 9.8 )1/2
= 1.01 s
Horizontal distance traveled by Tarzan = 1.01 × 7
= 7.07 m
Answer:
k = 104.46 N/m
Explanation:
Here we can use energy conservation
so we will have
initial gravitational potential energy = final total spring potential energy
as we know that she falls a total distance of 31 m
while the unstretched length of the string is 12 m
so the extension in the string is given as
so we have
Answer:
I hope This helps
Explanation:
The majority of oxidation-reduction (redox) reactions share two critical features. One is that a reduction happens in both, while equivalent oxidation occurs; they are combined.
Answer:
-2.478
0.379
11.14
24.78
Explanation:
Angular frequency of spring in harmonic motion is given by?
ω = √(k/m)
ω = √(10/2.2)
ω = √4.54
ω = 2.13 s^-1
If at t=0 the mass is in negative amplitude (x = -A = -2.48 m) then we describe the position with negative cosine
x(t) = -A * cos(ωt)
x(t) = -2.48 * cos(2.13 * 1)
x(t) = -2.48 * 0.9993
x(t) = -2.478
Velocity and acceleration are 1st and 2nd derivative of position
b)
v(t) = Aω * sin(ωt)
v(t) = 2.48 * 2.13 * sin(2.13 * 1)
v(t) = 5.282 * sin2.13
v(t) = 5.282 * 0.03717
v(t) = 0.379 m/s
c)
a(t) = Aω^2 * cos(ωt)
a(t) = 2.48 * 2.12² * cos(2.13 * 1)
a(t) = 2.48 * 4.494 * cos2.13
a(t) = 11.15 * 0.9993
a(t) = 11.14 m/s²
d)
F = -k * x(t)
F = -10 * -2.478
F = 24.78 N