Left border 16$
bottom border is 2$
Let
x---------> the larger number
y---------> the smaller number
we know that
x+y=148------> equation 1
x=3y-2------> equation 2
substitute 2 in 1
[3y-2]+y=148--------> 4y=150---------> y=150/4------> y=37.5
x=3y-2----> x=3*37.5-2-----> x=110.5
the answer is
the larger number is 110.5
the smaller number is 37.5
Answer:
it is -2
Step-by-step explanation:
Just use the Pythagorean theorem.
a^2 + b^2 = c^2
4^2 + x^2 = (2x-1)^2
16+x^2=(2x-1)(2x-1)
16+x^2=4x^2-4x+1
0=3x^2-4x-15
0=(3x+5)(x-3)
3x+5=0 x-3=0
3x= -5 x=3
x= -5/3 x=3
Since x can't be a negative number when it comes to distance or the length of a triangle, the answer must be x=3.
