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3 years ago

Find the unit rate of 42 teaspoons for 6 cups

Mathematics

1 answer:

attashe74 [19]3 years ago

6 0

The answer is 7 teaspoons for one cup

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MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

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6 0

2 years ago

X < -4.8

Kamila [148]

Answer:

D & E

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

7. A fundraising group charges $0.25 per cookie and has a daily expense of $18. Which of the

marissa [1.9K]

Answer:

Look below

Step-by-step explanation:

To answer the question, you have to find out how much 49 sold cookies amounts to, so multiply 49 by however much it is per cookie.

Then, subtract the daily expense, $18, by the number you got from the total amount earned from the cookies sold, and that number would show the daily profit earned by selling 49 cookies.

Hope this helps :)

4 0

3 years ago

Extra points! please help !!

Xelga [282]

Answer:

The maximum width of the pool must be 38 ft

Step-by-step explanation:

Let

y -----> the length of the swimming pool

x ----> the width of the swimming pool

The perimeter of the swimming pool is