Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
It was reduced because as you can see on the scale the actual picture has larger spaces between the numbers.
Answer:
The third angle of the triangle is 70°.
Step-by-step explanation:
The two angles of a triangle (say Δ ABC) are given to be 30° and 80°.
We have to find the third angle.
Let us assume that ∠ A = 30° and ∠ B = 80°, then we have to find ∠ C.
Now, we know that, ∠ A + ∠ B + ∠ C = 180° {Property of a triangle}
⇒ 30° + 80° + ∠ C = 180°
⇒ ∠ C = 180° - 30° - 80° = 70°
Therefore, the third angle of the triangle is 70°. (Answer)