1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nina [5.8K]
3 years ago
5

Sylvia asked a random sample of students whether they prefer eating vegetables or fruits as a snack, and whether they prefer to

bicycle or to walk. The results are shown in the table. Snack and Activity Preferences Bicycle Walk Total Vegetables 11 17 28 Fruits 16 10 26 Total 27 27 54 Approximately what percentage of the students surveyed prefer to eat vegetables and prefer to bicycle? A. 11% B. 20% O C. 30% OD. 41% O E. 51%​
Mathematics
2 answers:
Lorico [155]3 years ago
6 0

Answer: could be 20%, sorry if im wrong

Step-by-step explanation:

kkurt [141]3 years ago
3 0

Answer:

20%

Step-by-step explanation:

You might be interested in
A friend tells you to apply for a sales job at a certain company because the mean income of salespeople last year was $47,500. L
Andrew [12]

Answer:

it depends on if i think i could succeed in tha job

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Is 1.31 greater then 1.2?
BigorU [14]

Answer:

Yes because 1.31 and 1.2. 3 is more than 2

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Please help!!!! Anyone!!
Hoochie [10]

9514 1404 393

Answer:

  g(x) = |x -7|

Step-by-step explanation:

The form given for your answer has parameters 'a', 'h', and 'k'. The parameter 'a' is the vertical scale factor. Since g(x) is a translation only, that factor is 1. The parameters (h, k) identify the translation (right, up). The translation is 7 units right and 0 units up, so (h, k) = (7, 0).

Filling in these values of the parameters, your g(x) is ...

  g(x) = |x -7|

8 0
3 years ago
Help help help guys show you solution​
Mars2501 [29]

Answer:

Step-by-step explanation:

1) y  = 2x  ----------(I)

x + y = 6 -----------(II)

Plug in y =2x in equation (II)

x + 2x = 6        {Add like terms}

  3x    = 6

       x = 6/3

      x = 2

Plugin x = 2 in (I)

 y = 2*2

y = 4

<u>Check: </u>

     LHS = x +y

             = 2 + 4

            = 6  = RHS

2)5x + 10y = 3 ------------(I)

x = (-1/2) y     ------------(II)

Substitute x = (-1/2)y in (I)

5*\frac{-1}{2}y + 10y = 3\\\\\frac{-5}{2}y+ \frac{10*2}{1*2}y = 3\\\\\frac{-5}{2}y+\frac{20}{2}y=3\\\\\frac{-5+20}{2}y = 3\\\\\frac{15}{2}y=3\\\\    y = 3*\frac{2}{15}\\\\   y = \frac{2}{5}

Substitute y = (2/5) in equation (II)

x = \frac{-1}{2}*\frac{2}{5}\\\\x = \frac{-1}{5}

<u>Check:</u>

Substitute x and y value in equation (I)

LHS = 5*\frac{-1}{5}+10*\frac{2}{5}\\\\  = -1 + 2*2\\\\ = -1 + 4\\ = 3 = RHS

3) y - x = 3x + 2

        y = 3x + 2 + x

         y = 4x + 2 ---------------(I)

2x + 2y = 14 - y

2x + 2y +y = 14

2x + 3y = 14     ------------------(II)

Substitute y = 4x + 2 in equation (II)

2x + 3(4x +2) = 14

2x + 3*4x + 3*2 = 14

2x + 12x + 6 = 14

        14x + 6 = 14

              14x = 14 - 6

              14x = 8

                 x = 8/14

            x = 4/7

Substitute 'x' value in (I)

y = 4*\frac{4}{7} +2\\\\y = \frac{16}{7}+2\\\\y= \frac{16}{7}+\frac{2*7}{1*7}\\\\y=\frac{16}{7}+\frac{14}{7}\\\\y=\frac{30}{7}

<u>Check:</u>

<u />LHS = 2x + 3y\\\\      = 2*\frac{4}{7}+3*\frac{30}{7}\\\\  = \frac{8}{7}+\frac{90}{7}\\\\=\frac{8+90}{7}\\\\=\frac{98}{7}\\\\=14 = RHS<u />

6 0
3 years ago
Suppose that A and B each randomly, and independently, choose 3 of 10 objects. Find the expected number of objects (a) chosen by
makkiz [27]

Answer:

a) N(A∩B) = 0.9

b) N(A∩B) = 4.9

c) N(A or B) = 4.2

Step-by-step explanation:

Given that A and B each randomly, and independently, choose 3 of 10 objects;

P(A) = P(B) = 3/10 = 0.3

P(A') = P(B') = 1 - 0.3 = 0.7

a) chosen by both;

Probability of being chosen by both;

P(A∩B) = 0.3 × 0.3 = 0.09

Expected Number of objects being chosen by both;

N(A∩B) = P(A∩B) × N(total) = 0.09×10

N(A∩B) = 0.9

b) not chosen by either A or B;

Probability of not being chosen by either A or B;

P(A'∩B') = 0.7 × 0.7 = 0.49

Expected Number of objects being chosen by both;

N(A'∩B') = P(A'∩B') × N(total) = 0.49×10

N(A∩B) = 4.9

c) chosen by exactly one of A and B.

Probability of being chosen by exactly one of A and B

P(A∩B') + P(A'∩B) = 0.3×0.7 + 0.7 × 0.3 = 0.42

Expected Number of objects being chosen by both;

N(A or B) = 0.42 × 10

N(A or B) = 4.2

6 0
3 years ago
Other questions:
  • Eight less than 1/3 a number n is -13
    11·1 answer
  • F 2. mm B-Mmdkmdkhew III-II... RIVAL-hll Ill-Ill.- e a
    11·1 answer
  • What is the adult to child ratio of 8:5 if 390 attend how many are adults
    13·1 answer
  • In which year was the profit, the difference between the income and costs, the greatest?
    14·2 answers
  • 3/2 x 63 = how many?
    12·2 answers
  • The point (5, −2) is on the terminal ray of angle θ, which is in standard position. Without evaluating, explain how you would fi
    13·2 answers
  • How many whole numbers are less than n+1? WILL GIVE BARINALIEST TO WHOEVER ANSWERS FIRST AND IS CORRECT
    11·2 answers
  • The conference will begin at 8:30 a.m. and will last 5 hours 45 minutes. What time will the conference be over?
    10·1 answer
  • What is the domain of f?
    13·1 answer
  • 42 67 68 70 71 78 79 80 81 84 86 86 89 99 99<br>calculate the five number summary ​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!