The largest taco contained approximately 1 kg of onion for every 6.8 kg grilled steak. The total weight of these two ingredients was 617.6 kg. How many kilograms of each ingredient were used?
2 answers:
Answer: Onion = 79.17 kg
Grilled steak = 538.356 kg
Step-by-step explanation:
Hi, to answer this question we have to write an equation with the information given:
1 k + 6.8 k = 617.6
Where “k” is a constant value, a multiplier.
Solving for k:
7.8 k = 617.6
k = 617.6 /7.8
k= 79.17
So:
Amount of onion used:
1 (79.17) = 79.17 kg
Amount of grilled steak used:
6.8 (79.17) = 538.356 kg
Feel free to ask for more if needed or if you did not understand something.
Answer:
Step-by-step explanation:
For a taco:
Ingredient:
1 kg of onion for every 6.8 kg grilled steak
Wt = 617.6 kg
Let x = mass of onion and y = mass of grilled steak
x + 6.8y = 617.6
Can also be written as:
x + 6.8x = 617.6
x = 617.6/7.8
= 79.2.
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