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4 years ago

Ions are atoms that have gained or lost which subatomic particles?

2 answers:

7 0

Protons cannot be lost without the atoms becoming an entirely different element. Elements can infact have different numbers of neutrons within the same element, but neutrons are not related to the electrical charge. The answer is c. electrons.

melisa1 [442]4 years ago

7 0

Answer: The correct answer is Option C.

Explanation:

There are 3 subatomic particles present in an atom. They are: protons, electrons and neutrons.

Protons: They carry positive charger and are found in nucleus.
Electrons: They carry negative charge and are found around the nucleus.
Neutrons: They dos not carry any charge and are found in nucleus.

An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.
When an atom gains electrons, it will form a negative ion known as anion.

Hence, the correct answer is Option C.

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Phosphoric acid is a triprotic acid ( K a1 = 6.9 × 10 − 3 , K a2 = 6.2 × 10 − 8 , and K a3 = 4.8 × 10 − 13 ). To find the pH of

timama [110]

Answer:

Ka2 values should be used in obtaining pKa2 in the Henderson–Hasselbalch equation

Explanation:

During first dissociation from H3PO4 to H2PO4-, ka1 will be used, and from H2PO4-to HPO4-, ka2 values will be used, hence a buffer solution containing H2PO4-and HPO4-will use ka2 in obtaining pKa2 in the Henderson–Hasselbalch equation.

7 0

4 years ago

Determine the specific heat of a material if a 35-9 sample absorbed 96 ) as it was heated from 293 Kto 313 K.

Norma-Jean [14]

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

$q=m\times c\times (T_2-T_1)$

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = 313 K

Now put all the given values in the above formula, we get:

$96J=35g\times c\times (313-293)K$

$c=0.137J/g.K$

Therefore, the specific heat of a material is, 0.137 J/g.K

5 0

4 years ago

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

Temka [501]

The question is incomplete , complete question is:

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

(a) n = 2 to n = 4

(b) n = 2 to n = 1

(d) n = 4 to n = 3

Answer:

Hence the order of the transition will be : d < a < c < b

Explanation:

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen atom:

$E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6 eV$

Energy of n = 2 in an hydrogen atom:

$E_2=-13.6\times \frac{1^2}{2^2}eV=-3.40eV$

Energy of n = 3 in an hydrogen atom:

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV$

Energy of n = 4 in an hydrogen atom:

$E_4=-13.6\times \frac{1^2}{4^2}eV=-0.85 eV$

Energy of n = 5 in an hydrogen atom:

$E_5=-13.6\times \frac{1^2}{5^2}eV=-0.544 eV$

a) n = 2 to n = 4 (absorption)

$\Delta E_1= E_4-E_2=-0.85eV-(-3.40eV)=2.55 eV$

b) n = 2 to n = 1 (emission)

$\Delta E_2= E_1-E_2=-13.6 eV-(-3.40eV)=-10.2 eV$

Negative sign indicates that emission will take place.

c) n = 2 to n = 5 (absorption)

$\Delta E_3= E_5-E_2=-0.544 eV-(-3.40eV)=2.856 eV$

d) n = 4 to n = 3 (emission)

$\Delta E_4= E_3-E_4=-1.51 eV-(-0.85 eV)=-0.66 eV$

Negative sign indicates that emission will take place.

According to Planck's equation, higher the frequency of the wave higher will be the energy:

$E=h\nu$

h = Planck's constant

$\nu$ frequency of the wave

So, the increasing order of magnitude of the energy difference :

$E_4$

And so will be the increasing order of the frequency of the of the photon absorbed or emitted. Hence the order of the transition will be :

: d < a < c < b

7 0

4 years ago

The form of oxygen that combines three oxygen atoms to each molecule, is found in the stratosphere and shields out harmful UV ra

Dmitry_Shevchenko [17]

This form of the oxygen molecule is Ozone, O3.

7 0

3 years ago

A beaker of water has a volume of 125mL and a density of 1.0g/mL. Calculate the mass of the water.

liq [111]

Answer: 125 g

Explanation:

Mass = Volume × Density

⇒ Mass of the water = 125 mL × 1.0 g/mL

= 125 g

7 0

3 years ago