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Semmy [17]
3 years ago
15

Ions are atoms that have gained or lost which subatomic particles?

Chemistry
2 answers:
Bad White [126]3 years ago
7 0
Protons cannot be lost without the atoms becoming an entirely different element. Elements can infact have different numbers of neutrons within the same element, but neutrons are not related to the electrical charge. The answer is c. electrons.
melisa1 [442]3 years ago
7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

There are 3 subatomic particles present in an atom. They are: protons, electrons and neutrons.

  • Protons: They carry positive charger and are found in nucleus.
  • Electrons: They carry negative charge and are found around the nucleus.
  • Neutrons: They dos not carry any charge and are found in nucleus.

An ion is formed when an atom looses or gains electron.

  • When an atom looses electrons, it will form a positive ion known as cation.
  • When an atom gains electrons, it will form a negative ion known as anion.

Hence, the correct answer is Option C.

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Phosphorus can be prepared from calcium phosphate by the following reaction:

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

Phosphorite is a mineral that contains Ca_3(PO_4)_2 plus other non-phosphorus-containing compounds. What is the maximum amount of P_4 that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% Ca_3(PO_4)_2 by mass? Assume an excess of the other reactants.

Answer: Thus the maximum amount of P_4 that can be produced is 0.345 kg

Explanation:

Given mass of phosphorite Ca_3(PO_4)_2  = 2.3 kg

As given percentage of phosphorite Ca_3(PO_4)_2 is = \frac{75}{100}\times 2.3kg=1.725kg=1725g

moles=\frac{\text {given mass}}{\text {Molar mass}}

{\text {moles of}Ca_3(PO_4)_2=\frac{1725g}{310g/mol}=5.56moles

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

According to stoichiometry:

2 moles of phosphorite gives = 1 mole of P_4

Thus 5.56 moles of phosphorite give= \frac{1}{2}\times 5.56=2.78moles of P_4

Mass of P_4=moles\times {\text {Molar mass}}=2.78mol\times 124g/mol=345g=0.345kg

Thus the maximum amount of P_4 that can be produced is 0.345 kg

5 0
2 years ago
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