Im pretty sure that is true. but the oil will no longer be pure, as it was mixed with water.
Answer:
Yup! The answer is 50 J/g* °C
Explanation:
I also took the test but I know how to work out the problem for anyone who wants to know how to solve it.
Remember the formula q = m*C*ΔT
m = the mass in grams
C = the specific heat Capacity
ΔT = change in time
q = amount of energy
So, find out what was given and what we need to look for:
m = 40 g
C = ?
ΔT = we're heating up (the temperature increases) a chemical so it needs to be a positive number. 25 - 10 = 15 °C
q = 30000 Joules
Now, set up the equation:
q = m*C*ΔT
30000 = 40 * C * 15
Multiply 40 and 15 to get 600:
30000 = 600 * C
Divide both sides by 600 to get C by itself (plug this into your calculator):
30000/600 = 600 * C/600
You are left with 50 = C
Now, you just need to plug in the units to get B. 50 J/g* °C
I hope I helped clear up any confusion! :D
Percentage by mass of water in CuSO4.5H20 is 36.07% .
In this problem we have - copper(II) sulfate pentahydrate and it's molecular formula is (CuSO₄.5H₂O) .
There are 5 molecules of water are present.
Now we calculate it's molar mass-
We know that-
molar mass of Cu = 63.5u
Molar mass of SO₄ = 96 u
Molar mass of H₂O = 18 u
Now, molar mass of (CuSO₄.5H₂O) = 63.5 + 96 + 5 × 18
Now, molar mass of (CuSO₄.5H₂O) = 249.5u
And mass of water in CuSO₄.5H₂O = 90 u
now mass percentage of water = mass of water ÷ Total mass ×100
now mass percentage of water = 90 ÷ 249.5 × 100
now mass percentage of water = 36.07 %
So we find out mass percent by dividing given mass with total mass and then multiplying it with hundred and it came out to be 36.07 % .
Learn more about mass percent here: brainly.com/question/13896694
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