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2 years ago

What do you look at to tell the reactivity of an atom?

Chemistry

1 answer:

tia_tia [17]2 years ago

8 0

Answer:

The number of electrons in the outermost shell of an atom determines its reactivity. Noble gases have low reactivity because they have full electron shells. Halogens are highly reactive because they readily gain an electron to fill their outermost shell.

Explanation:

I hope this helped!

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Will Upvote!

Dvinal [7]

If my memory serves me well, the correct answer is: Chemical processes store and release C: energy in the bonds of molecules.

8 0

2 years ago

Read 2 more answers

How many moles are in 45.8 g of calcium nitrate, Ca(NO3),?

Deffense [45]

Answer:

the number of moles is 0.279

Explanation:

The calculation of the number of moles of calcium nitrate, is given below;

As We know that

Number of moles = mass of substance ÷ molecular weight

where

Mass of substance is 45.8g

And, the molecular weight is 164.088

so,

= 45.8 g ÷ 164.088

= 0.279moles

Thus , the number of moles is 0.279

We simply used the above formula so that the accurate value could arrive

4 0

2 years ago

A solution of ethanol (c2h5oh) in water is prepared by dissolving 75.0 ml of ethanol (density 0.79 g/cm3 ) in enough water to ma

navik [9.2K]

Given the density of ethanol = 0.79 $\frac{g}{cm^{3} }$

Volume of ethanol = 75.0 mL

Calculating the mass if ethanol from density and volume:

$75.0 mL * \frac{0.79g}{1cm^{3} } *\frac{1cm^{3} }{1mL}=59.25g$

Molar mass of ethanol = (2*atomic weight of C)+(6*atomic weight of H)+(1*atomic weight of O)

=(2*12g.mol) + (6*1g/mol) + (1*16g/mol)

=46g/mol

Moles of ethanol = $59.25 g *\frac{1 mol}{46g} =1.288 mol$

Volume of the solution = 250.0 mL

Converting the volume from mL ot L:

$250.0mL*\frac{1L}{1000mL}=0.2500L$

Molarity of ethanol in the solution = $\frac{1.288mol}{0.250L} =5.15 M$

5 0

2 years ago

Determine the empirical and molecular formula for a compound containing 26.1

kobusy [5.1K]

determing that the compoumd formed is in 100%

therefore, 26.1 +4.3+69.6 = 100%

hence no need of adding O molecule

finding the numbr of moles of each element

no. of moles of C= given mass÷molar mass

=26.1÷12

=2.1 mol

no. of moles of H = given mass÷molar mass

=4.3÷1

=4.3 mol

no of moles of O =given mass÷molar mass

=69.6÷16

=4.3

the simplest whole nber of the element in the unknown compoumd is 1:2:2 of C:H:O

HENCE, the empirical formula is CH2O2

empirical formula mass of CH2O2 IS

=(12)+(2×1)+(16×2)

12+2+32

46 G/MOL

N= molar mass of the compoumd ÷ emporical mass of the compoumd

N= 138÷46

N=3

molecular formula =N×empirical formula

=3 ×CH2O2

C3H6O6 is the molecular formula

(tartonic acid)

hope it helped u!

5 0

1 year ago

Reasons and how we arrange elements according to their positions in the electrochemical series

Sladkaya [172]

Answer:

$mile please :)

Explanation:

$mile please :)

6 0

2 years ago