Answer:
6.88 mg
Explanation:
Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄
The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.
175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P
Step 2: Calculate the rate constant for the decay of ³²P
The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.
k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹
Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days
For first-order kinetics, we will use the following expression.
ln P = ln P₀ - k × t
ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d
P = 6.88 mg
Answer:
the answer is : true ice and snow melts into water in sublimation
Answer:
a) a space in an atom where an electron is most likely to be found
Explanation:
Atomic orbital is the mathematical function which describes wave-like behavior of the electrons present in the atom.
It is used to calculate probability of finding the electron of the atom in any region around nucleus of the atom. Atomic orbital is the physical region or a three dimensional space where the probability of finding the electron is more than 90% which also means that the space where an electron is most likely to be found. They are boundless space and have definite energy.
Option A best describes atomic orbital.
~Hello there!
Your question: Scientifically is light the fastest thing in the world?
Your answer: Yes! Light is the fastest thing in the world!. Its even proved in the modern physics. Even if the light going through an empty space, its velocity will be constant and steady.
Any queries?
Happy Studying ^=^
Answer is: <span>D. 327,992.8 J.
</span>m(granite) = 17 kg = 17000g.
ΔT(granite) = 21°C - 45°C = -24°C (-24K).<span>
cp(granite</span>)
= 0,804 J/g·°C, <span>specific heat capacity of
granite.
Q = m(granite</span>) · ΔT(granite) · cp(granite).<span>
Q = 17000 g ·(-24</span>°C)<span>· 0,804 J/g·K.
Q = -327990 J.
</span>The granite lost 327990 joules of energy.<span>
Q - </span>amount of energy gained or lost.<span>
</span>
