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3 years ago

What are the zero(s) of the function 5x2-25x/x

Mathematics

1 answer:

Vikentia [17]3 years ago

6 0

The answer is A: 5

Any answer with 0 doesn't work because then the denominator would be 0 as well, and negative 5 does not make the numerator equal to 0.

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For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so:

$\theta\neq \pi$

having said this, we can now start solving the equation:

$tan(\frac{\theta}{2})=sin(\theta)$

we can start solving this equation by using the half angle formula, such a formula tells us the following:

$tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}$

so we can substitute it into our equation:

$\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)$

we can now multiply both sides of the equation by $sin(\theta)$

so we get:

$1-cos(\theta)=sin^{2}(\theta)$

we can use the pythagorean identity to rewrite $sin^{2}(\theta)$ in terms of cos:

$sin^{2}(\theta)=1-cos^{2}(\theta)$

so we get:

$1-cos(\theta)=1-cos^{2}(\theta)$

we can subtract a 1 from both sides of the equation so we end up with:

$-cos(\theta)=-cos^{2}(\theta)$

and we can now add $cos^{2}(\theta)$

to both sides of the equation so we get:

$cos^{2}(\theta)-cos(\theta)=0$

and we can solve this equation by factoring. We can factor $cos(\theta)$ to get:

$cos(\theta)(cos(\theta)-1)=0$

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

$cos(\theta)=0$

$\theta=cos^{-1}(0)$

$\theta={\frac{\pi}{2}, \frac{3\pi}{2}}$

Equation 2:

$cos(\theta)-1=0$

we add a 1 to both sides of the equation so we get:

$cos(\theta)=1$

$\theta=cos^{-1}(1)$

$\theta=0$

so we end up with three answers to this equation:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

7 0

2 years ago

The denominator of a fraction is 4 more than the numerator if both are decreased by 3 the simplified result is 6/7 find original

Hitman42 [59]

<u>Answer:</u>

The denominator of a fraction is 4 more than the numerator. The original fraction is $\frac{27}{31}$

<u>Solution:</u>

Given that

Denominator of fraction is 4 more than the numerator.

Let’s say numerator of fraction be represented by variable x.

So denominator of a faction as it is four more that numerator will be x + 4

Also given if both decreased by three than simplified result is $\frac{6}{7}$

$=>\frac{(x-3)}{((x+4)-3)}=\frac{6}{7}$

Solving above equation for x

=> 7(x – 3 ) = 6 ( x + 1 )

=> 7x – 21 = 6x + 6

=> 7x – 6x = 6 + 21

=> x = 27

Numerator of fraction = x = 27

Denominator of fraction = x + 4 = 27 + 4 = 31

$\text {required fraction}=\frac{\text {numerator}}{\text {denominator}}$

$= \frac{27}{31}$

Hence the original fraction is $\frac{27}{31}$

7 0

3 years ago

Jack deposited $1,400 in his bank account. After 3 years, the account is worth $1,694. Find the simple interest rate the account

fenix001 [56]

Answer:

D. 7%

Step-by-step explanation:

5 0

2 years ago

Which statement is true about the function f(x)= squared root negative x?

Liono4ka [1.6K]

The answer is the first option: it has the same domain as the function f(x) = - √(-x).

The domain is the set of x-values for which the function is defined.

The square root function is defined only for zero and positve values.

- x is positive when x negative.

So the domain for - √(-x) and √(-x) are the same: x less than or equal to zero.

4 0

2 years ago

2.3 - 5m = 9.8 + 2.5m

Angelina_Jolie [31]

Answer:

m=-1

Step-by-step explanation:

2.3-5m=9.8+2.5m

+5m=9.8+5m

2.3=9.8+7.5m

-9.8 -9.8

-7.5=7.5m

/7.5 /7.5

-1=m

5 0

3 years ago

Read 2 more answers