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torisob [31]
3 years ago
8

If a(x)=3x+1 and b(x)=

" alt=" \sqrt{x - 4} " align="absmiddle" class="latex-formula">
what is the domain of (b○a)(x)?​
Mathematics
1 answer:
ipn [44]3 years ago
7 0
Answer: Domain: {x | x ≥ 1}

Explanation: First, we must write the equation for (b ° a)(x).

Write b(x).

b(x) = √(x - 4)

Substitute x in b(x) for a(x) to get (b ° a)(x).

(b ° a)(x) = √(3x + 1 - 4)

Simplify the right side of the equation.

(b ° a)(x) = √(3x - 3)

To find the domain, write this function as an inequality greater than or equal to 0.

√(3x - 3) ≥ 0

Raise both sides to the power of 2.

3x - 3 ≥ 0

Add 3 to both sides.

3x ≥ 3

Divide both sides by three.

x ≥ 1

Write this inequality as your domain in set notation.

Domain: {x | x ≥ 1}
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Answer:

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Step-by-step explanation:

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2 years ago
Math help will give brainliest what is X and M angle A
Anna [14]
Supplementary = 180 degrees...

A + B = 180

3x + 12 + 7x + 38 = 180

10x + 50 = 180

10 x = 130

x = 13 

To find the A just substitute x in...

 
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3 0
3 years ago
Divide. (6.496×10−6)÷(2.8×105) Express your answer in scientific notation. Enter your answer in the boxes.
ss7ja [257]

we have been asked to perform (6.496*10^{-6})\div (2.8*10^5)

The given expression can be written as

\frac{(6.496*10^{-6})}{2.8*10^5}

Now it can be re-written as below

=\frac {(6.496*10^{-6})}{2.8*10^5}=\frac{6.496}{2.8}*\frac{10^{-6}}{10^5}\\ \\ \text{Now using the exponent rule }  \\ \\ \frac{a^m}{a^n}=a^{m-n}\\ \\ \text{we can re-write as below}\\ \\  \frac{6.496}{2.8}*\frac{10^{-6}}{10^5}= \frac{6.496}{2.8}*10^{-6-5}= \frac{6.496}{2.8}*10^{-11}\\ \\ \text{Now divide we get}\\ \\ =2.32*10^{-11}

6 0
3 years ago
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