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leonid [27]
3 years ago
13

Lola needs to sign 96 invitations. Using a stopwatch that measures time to tenths of a second, it takes Lola 5.3 seconds to sign

her full name. Going by the accuracy of the stopwatch, which is the most accurate determination for the number of minutes Lola needs to sign all 96 invitations? 3.3 minutes 3.3125 minutes 8.48 minutes 8.5 minutes
Mathematics
2 answers:
barxatty [35]3 years ago
9 0

Answer:

<em>I believe the answer is 8.48 seconds</em>

I hope this helps.

If the answer is correct, please vote me brainliest!

kirill [66]3 years ago
7 0

Answer:

C. (8.84)

Step-by-step explanation:

Since we have given that

Total number of invitations = 96

Time taken to sign her full name = 5.3 seconds

Total time she needed to sign in 96 invitations is given by

(96 times 5.3 = 508.8 seconds)

And we know that

(1 min= 60 seconds)

(508.8 seconds =508.8/60 = 8.48 minutes)

So, Lola will be able to finish signing all the invitations after 8.84 minutes.

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Monica says,"if 4 bottles cost $10, then 2 bottles cost $5 + $20." Is Monica correct? Explain
Igoryamba

Answer:

Monica is not correct.

Step-by-step explanation:

First of all, if 4 bottles only cost $4, then how would only 2 cost more? (She said the two bottles would be $25, which doesn’t make sense.)

8 0
3 years ago
When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0
3 years ago
Y=-4x+6<br> Find an equation for the inverse relation
kherson [118]

Answer:

Step-by-step explanation:

y = -4x + 6.....switch x and y and solve for y

x = -4y + 6 ....subtract 6 from both sides

x - 6 = -4y....divide by -4 on both sides

(x - 6) / -4 = y or y = -1/4x + 3/2 <====

3 0
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What is the square root of 325 rounded to two decimal places?
hammer [34]
The square root of 325 is 18.03
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a snail travels 3 1/3 ft every hour how far does the snail travel in 2 1/2 hours answer simplest form
Anni [7]
3 and 1/3 times 2.5 = 8.3(repeating 3) feet
5 0
3 years ago
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