Answer:
(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
Step-by-step explanation:
Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.
The probability that a customer makes a purchase is, <em>p</em> = 0.52.
The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.
The probability mass function of <em>X</em> is:
The expected value of a Geometric distribution is:
(a)
Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:
This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b)
Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:
Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
Answer:
1. 5²
2. 5⁴
3. 1/5⁶
4. 5⁰
5. 5¹⁰
Step-by-step explanation:
1. 5⁶⁺⁽⁻⁴⁾=5²
2. 5¹⁺³=5⁴
3. 5⁻³⁺⁽⁻³⁾=5⁻⁶=1/5⁶
4. 5⁽⁻⁴⁾⁺⁴⁺⁰=5⁰
5. 5⁷⁺³=5¹⁰
Answer:
−
6 =
0
Step-by-step explanation:
Answer:
16.3 = 16
Step-by-step explanation:
0.1 is equivalent to 1/10 or one tenth so 0.3 = 3/10
Answer:
(5, 1 )
Step-by-step explanation:
Given the 2 equations
3y - 2x = - 7 → (1)
5x + 3y = 28 → (2)
Rearrange (1) expressing 3y in terms of x by adding 2x to both sides
3y = - 7 + 2x
Substitute 3y = - 7 + 2x into (2)
5x - 7 + 2x = 28
7x - 7 = 28 ( add 7 to both sides )
7x = 35 ( divide both sides by 7 )
x = 5
Substitute x = 5 into either of the 2 equations and solve for y
Substituting into (2)
5(5) + 3y = 28
25 + 3y = 28 ( subtract 25 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
solution is (5, 1 )