Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Interval notation
(-infinity sign, 1)
Set-builder notation
{x|x less than equal to 1}
Answer: 5/18
Step-by-step explanation:
The sample space when two 6- sided dice are rolled is given below:
(+) 1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
The total sample space is 36.
Sum greater than 8 are : {9,10,11,12}
which are 10 in number:
Therefore : the probability that the sum of the two numbers on the dice will be greater than 8 will be :
number of the sum greater than 8 / Total sample space
That is ;
P(sum greater than 8) = 10/36
P(sum greater than 8) = 5/18
Answer:
12.7 cm
Step-by-step explanation:
ABC
12² = 6² + BC²
12² - 6² = BC²
144 - 36 = 108
CB² = 108
√108 = 10.392
CB = 10.392
CBD
Sin (55°) = CB / CD
0.81915 = √108 / CD
CD = 10.392 / 0.81915
CD = 12.686
CD = 12.7cm
Answer:
4
Step-by-step explanation:
AO = OC
3x - 4 = 8
x = 4
