Ben is traveling home on M1 and M42 both motorways have roadworks he has fifty-fifty chance of getting delayed on the M42 and 75
% chance of being delayed on the M1. What are the chances he will not be delayed on his journey?
1 in 4
3 in 8
1 in 8
1 in 2
Please show your working out
1 answer:
P(being delayed on M1) = 0.5 →P(NOT being delayed on M1) = 1-0.5 = 0.5
P(being delayed on M42)=0.75→P(NOT being delayed on M42) = 1-0.75= 0.25
P(NOT being delayed on M1) AND P(NOT being delayed on M42) = 0.5x0.25
→ 0.125 = 1/8
So, the chances he will not be delayed on his journey is 1/8
You might be interested in
Equation for a
a= b/c - 1
Equation for b
b= ca - a
Equation for c
c= b/a + 1
Answer:
6^2 is the answer
Step-by-step explanation:
just trust me ik
The answer is 21 because I added 8 + 10+3=and I got 21
642+10= 652//////////////
4 Days I found this out by this