<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
37/5 or 7.4 or 7 2/5
Step-by-step explanation:
<em>I hope this helps! Have a great day!!</em>
<em>Skye~</em>
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
Change 
so that is has a common denominator. 
Make an equation. 
Add. 
Add. 
Divide both sides by 2. 
Convert to a mixed number. 
Answer:
The correct option is;
The line of best fit is not reasonable because it has more points below it than above it.
Step-by-step explanation:
Here we note that there are a total of seven points in the scatter plot and there are five of the points below the line of best fit and just two above the line.
Of the five points below the line of best fit, four are just about touching the underside of the line while one of the two points above the line is just about touching the line.
The proper positioning of the line can be reviewed, therefore, with a line drawn through the four points presently touching the underside of the line of best fit.
