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krek1111 [17]
2 years ago
7

The coordinates of one endpoint of a line segment are (4, −12). The length of the segment is 5 units. Determine four coordinate

pairs that could serve as the other endpoint of the given line segment. Enter all four coordinate pairs in the box using a comma to separate each pair. For example: (0, 0), (1, 1), (2, 2), (3, 3)
Mathematics
1 answer:
Nina [5.8K]2 years ago
6 0

Answer:

Four coordinate pairs that could serve as the other endpoint of the given line segment are given by: (9,-12), (-1,-12), (4,-7), (4,-17).

Step-by-step explanation:

One endpoint of (4,-12), length of 5 units.

Four possible pairs:

Add 5 to x, keep y: (4+5,-12) = (9,-12).

Subtract 5 from x, keep y: (4-5,-12) = (-1,-12).

Keep x, add 5 to y: (4,-12+5) = (4,-7)

Keep x, subtract 5 from y: (4,-12-5) = (4,-17)

Four coordinate pairs that could serve as the other endpoint of the given line segment are given by: (9,-12), (-1,-12), (4,-7), (4,-17).

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= 2.003 \times  {10}^{1}

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The least common denominator of two fractions is 28. If you subtract the two denominators, their difference is 10. What are the
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The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. ​(
Vinvika [58]

Answer:

a) P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

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And if we use the z score we got:

P(z>2.431) =1-P(z

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

X \sim N(106,0.3)  

Where \mu=106 and \sigma=0.3

Part a

We are interested on this probability

P(X>106.11)

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And using this formula we got:

P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score we got:

z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

6 0
2 years ago
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