All categories

3 years ago

Please answer this please ASAP

Mathematics

2 answers:

love history [14]3 years ago

7 0

2c-11 because you convert all the c

pychu [463]3 years ago

3 0

I believe the answer is 2C-11

You might be interested in

What is an exact solution for <br><img src="https://tex.z-dn.net/?f=m%20%5Csqrt%7B14%7D%20" id="TexFormula1" title="m \sqrt{14}

AlexFokin [52]

Answer: Choice B) $\sqrt{14}$

We have some value m and we're squaring it to get $m^2$

To undo this and isolate m, we apply the square root to both sides

$m^2 = 14\\\\\sqrt{m^2} = \sqrt{14}\\\\|m| = \sqrt{14}\\\\m = \sqrt{14} \text{ or } m = -\sqrt{14}$

There are two solutions here. This is similar to how there are two solutions in something like $x^2 = 25$ (those two solutions being x = 5 and x = -5). Squaring any negative number leads to a positive result because

negative times negative = positive.

8 0

3 years ago

A gallon of Moo Milk costs \$5.12$5.12dollar sign, 5, point, 12. What is the price, in dollars, of an 888 ounce glass of Moo Mil

Sladkaya [172]

The correct statement is:
A gallon of Moo Milk costs $5.12 What is the price, in dollars, of an 8 ounce glass of Moo Milk? There are 128 ounces in 1 gallon.

Solution:
Cost of 1 gallon of Moo Milk = $ 5.12

1 gallon = 128 ounces, so we can write:

Cost of 128 ounces of Moo Milk = $ 5.12

Cost of 1 ounce of Moo Milk = $ 5.12/128 = $ 0.04

Cost of 8 ounces of Moo Milk = $ 0.04 x 8 = $ 0.32

Thus, 8 ounces of Moo Milk will cost $ 0.32

3 0

3 years ago

Read 2 more answers

The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

$\frac{4}{3}\times (4)^3=(0.1)^2h$

$h=8533.33cm\approx 8533cm$

Therefore, the length of the wire is, 8533 cm

6 0

3 years ago

Water flows into a tank according to the rate F of t equals the quotient of 6 plus t and the quantity 1 plus t, and at the same

diamong [38]

Answer:

Step-by-step explanation:

The complete question is

Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.

Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by

$\frac{dC}{dt}=[\tex]rate at which water flows in- rate at which water flows out. Then [tex]\frac{dC}{dt}=\frac{t+6}{t+1}-\frac{\ln(t+2)}{(t+1)}[\tex]so, the desired expression is obtained by integrating with respect to t. This leads us to [tex]C(t) = \int \frac{t+1}{t+1}+ \frac{5}{t+1} - \frac{\ln(t+2)}{(t+1)} dt=t+ 5 \ln (|t+1|)-\int \frac{\ln(t+2)}{(t+1)} dt +C$

Unfortunately, the integral $\int \frac{\ln(t+2)}{(t+1)} dt$ cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the polylogarithm function with n=2).

Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0

8 0

3 years ago

45 divided by 2531 HELP IDK HOW TO DO THIS.

SpyIntel [72]

0.017779534 because you just divide it

3 0

3 years ago