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2 years ago

How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas?

Chemistry

2 answers:

Elina [12.6K]2 years ago

4 0

Answer: 631.8 g

Explanation:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

It can be seen from the balanced chemical equation, 2 moles of ethane reacts with 7 moles of Oxygen gas to produce 4 moles of carbon dioxide and 6 moles of water.

Ethane is the limiting reagent as it limits the formation of product.

Thus, if 2 moles of ethane produce 6 moles of water.

11.7 moles moles of ethane produce= $\frac{6}{2}\times 11.7=35.1 moles$ of water.

Mass of water= no of moles $\times$ Molar mass

Mass of water= 35.1 $\times$ 18g/mol= 631.8 g

DENIUS [597]2 years ago

3 0

SO the way we balance this is like this:
2C2H6 + 7O2 → 4CO2 + 6H2O
x/11.7 = 6/2 x = 35.1 moles of of water are produced
35.1 mol * 18 g/mol = 631.8 g of water are produced.
Please take into account that:
2 moles of ethane gives =6 moles of water
11.7 moles of ethane gives = X moles of water (assume) cross multiplication =(6*11.7)/2
=35.1 moles
I hope this can help you greatly

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A 0.327-g sample of azulene (C10H8) is burned in a bomb calorimeter and the temperature increases from 25.20 °C to 27.60 °C. The

liq [111]

Explanation:

The given data is as follows.

Molecular weight of azulene = 128 g/mol

Hence, calculate the number of moles as follows.

No. of moles = $\frac{mass}{\text{molecular weight}}$

= $\frac{0.392 g}{128 g/mol}$

= 0.0030625 mol of azulene

Also, $-Q_{rxn} = Q_{solution} + Q_{cal}$

$Q_{rxn} = n \times dE$

$Q_{solution} = m \times C \times (T_{f} - T_{i})$

$Q_{cal} = C_{cal} \times (T_{f} - T_{i})$

Now, putting the given values as follows.

$Q_{solution} = 1.17 \times 10^{3} g \times 10^{3} \times 4.184 J/g^{o}C \times (27.60 - 25.20)^{o}C$

= 11748.67 J

So, $Q_{cal} = 786 J/^{o}C \times (27.60 - 25.20)^{o}C$

= 1886.4 J

Therefore, heat of reaction will be calculated as follows.

$-Q_{rxn}$ = (11748.67 + 1886.4) J

= 13635.07 J

As, $Q_{rxn} = n \times dE$

13635.07 J = $-n \times dE$

dE = $\frac{13635.07 J}{0.0030625 mol}$

= 4452267.75 J/mol

or, = 4452.26 kJ/mol (as 1 kJ = 1000 J)

Thus, we can conclude that $\Delta E$ for the given combustion reaction per mole of azulene burned is 4452.26 kJ/mol.

7 0

3 years ago

3.) this graph shows the rates of reaction in a chemical reaction with and without the addition of an enzyme

mars1129 [50]

Answer:

a. Concave down

Linear increasing

b. Increases the reaction rate

c. The reaction approaches the saturation point of the enzyme

Explanation:

a. For the reaction with enzyme, the shape is concave down. The action of the enzyme on the preferred substrate is initially very rapid and decreases as the enzyme becomes saturated and the ratio of products to substrate increases to approach an equilibrium rate of reaction

For the reaction without enzyme, the shape is linear and increasing. Increase in the concentration of the substrate will increase the number of effective collisions that lead into product formation leading to an increased rate of the chemical reaction

b. The enzyme increases the proportion of effective combination of substrates to form the products

c. The curve of the reaction with enzyme flattens out because as the concentration of the substrate increases while that of the enzyme remains the same, the enzyme becomes saturated and less able to increase the rate of the reaction of the excess substrate.

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2 years ago

How many moles of C2H2 are needed to react completely with 84.0 mol O2?

Mama L [17]

The reaction between C2H2 and O2 is as follows:
2C2H2 + 5O2 = 4CO2 + 2H2O

After balancing the equation, the reaction ratio between C2H2 and O2 is 2:5.

The moles of O2 in this reaction is 84.0 mol. According to the above ratio, the moles of C2H2 needed to react completely with the O2 is 84.0mole *2/5 = 33.6 mole.

6 0

3 years ago

Read 2 more answers

How would you characterize a liquid?

Naya [18.7K]

Answer:

The correct answer is D!

Explanation:

Liquids have a fixed shape and fixed volume. Liquids take the shape of their containers. Hope you have a great dayy!

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2 years ago

How many significant figures are in the number 0.00230? O 6

EleoNora [17]

Answer:

0.00230 = 3 significant figures

Explanation:

Significant digits or figures of a given number are the digits or figures that have meaning and contributes to the precision of the given number.

Therefore, 0.00230 = 3 significant figures.

Reason: The non-zeros figures and the trailing zero after the decimal are significant. Whereas, all the leading zeros are not considered significant.

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2 years ago