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Anton [14]
4 years ago
15

What is 4.41 times 10 to the negative second power

Mathematics
1 answer:
Zigmanuir [339]4 years ago
4 0
  4.41*ten  to the negative second power             = 0.0441
  
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(-8,1) it being reflected to the other side so just move the points 
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Simplify. ( w^2/-3u^4)^2. Write your answer without parentheses.
Rudiy27

Answer:

w^4 / (9u^8)

Step-by-step explanation:

( w^2/-3u^4)^2

We know that ( a/b) ^c = a^c  / b^c

( w^2) ^2/ (-3u^4)^2

We know that a^b^c = a^(b*c)  

w^(2*2)/ (-3u^4)^2

We know ( ab) ^c = a^c * b^c

w^4/ (( -3)^2 u^4^2)

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3 years ago
What is the length of y in this circle?<br><br> See attached for picture and choices
love history [14]

Answer:

The length of y is 8

Step-by-step explanation:

∵ The two chords of the circle intersected at a point

∴ 4 × 12 = 6 × y

∴ y = 48 ÷ 6 = 8

4 0
4 years ago
Answer plsss........ ​
Alex Ar [27]

1. x+12

2. x-8

3. 3*x

4. x^(2)+5

5. (x/2)+7

6. 4*(x+6)

7. (1/2)*x

8. 2x+8

9. x^(2)+3

10. (x/3)+12

Additional activity

1. 2-50

2.20/4=5

3.100-50=50

4.three times two then add to four equals ten

5. the diffrence of eight and four

7 0
3 years ago
A furniture company manufactures desks and chairs. Each desk uses four units of wood, and each chair uses three units of wood. A
Pavlova-9 [17]

Answer:

$180000

Step-by-step explanation:

Let's c be the number of chair and d be the number of desks.

The constraint functions:

- Unit of wood available 4d + 3c <= 2000 or d <= 500 - 0.75c

- Number of chairs being at least twice of desks c >= 2d or d <= 0.5c

c >= 0

d >= 0

The objective function is to maximize the profit function

P (c,d) = 400d + 250c

We draw the 2 constraint functions (500 - 0.75c and 0.5c) on a c-d coordinates (witch c being the horizontal axis and d being the vertical axis)  and find the intersection point 0.5c = 500 - 0.75c

1.25c = 500

c = 400 and d = 0.5c = 200 so P(400, 200) = $250*400 + $400*200 = $180,000

The 500 - 0.75c intersect with c-axis at d = 0 and c = 500 / 0.75 = 666 and P(666,0) = 666*250 = $166,500

So based on the available zones in the chart we can conclude that the maximum profit we can get is $180000

7 0
4 years ago
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