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3 years ago

For the following hypothetical reaction:

Chemistry

2 answers:

ycow [4]3 years ago

8 0

For the reaction:

3A +5B--->12C

Here 3 moles of A are reacting with 5 moles of B to produce 12 moles of C.

so, 1 mole of A will produce = 12÷3 moles of C

= 4 moles of C

so 2 moles of A will produce = 4×2 moles of C

= 8 moles of C

so, 2 moles of A are reacting with excess of B to produce 8 moles of C.

so , the answer is 2 moles of A are reacting with excess of B to produce 8 moles of C.

nata0808 [166]3 years ago

3 0

Answer:

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

Explanation:

3A+5B → 12C

We are given with excess moles of compound B and 2 moles of compound A.

Moles of compound A = 2 moles

According to reaction, 3 moles of compound A gives 12 moles of compound C.

Then 2 moles of compound A will give:

$\frac{12}{3}\times 2mol=8 mol$ of compound C.

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

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Please help, this assignment is to hard for me. :(

iren [92.7K]

Answer:

603000 J

Explanation:

The following data were obtained from the question:

Energy required (Q) =...?

Mass (M) = 10000 g

Specific heat capacity (C) = 2.01 J/g°C

Overheating temperature (T2) = 121°C

Working temperature (T1) = 91°C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) =T2 – T1

Change in temperature (ΔT) = 121 – 91

Change in temperature (ΔT) = 30°C

Finally, we shall determine the energe required to overheat the car as follow:

Q = MCΔT

Q = 10000 × 2.01 × 30

Q = 603000 J

Therefore, 603000 J of energy is required to overheat the car.

7 0

3 years ago

A gas has a pressure of 7.01 atm at 227°C. What will its temperature be if the pressure is increased to 12.1 atm and volume is h

kirill [66]

Answer:

The temperature of the gas will be 590.05 C.

Explanation:

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P= Pressure, T = temperature, K = Constant

This law indicates that the ratio between pressure and temperature is constant.

This law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of shocks against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature decreases, gas pressure decreases.

It is desired to study two different states, an initial state and an final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. When the temperature varies to a new T2 value, then the pressure will change to P2, and the following will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$