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fgiga [73]
3 years ago
7

For the following hypothetical reaction:

Chemistry
2 answers:
ycow [4]3 years ago
8 0

For the reaction:

3A +5B--->12C

Here 3 moles of A are reacting with 5 moles of B to produce 12 moles of C.

so, 1 mole of A will produce = 12÷3 moles of C

                                               =  4 moles of C

so 2 moles of A will produce = 4×2 moles of C

                                                 = 8 moles of C

so, 2 moles of A are reacting with excess of B to produce 8 moles of C.

so , the answer is 2 moles of A are reacting with excess of B to produce 8 moles of C.

nata0808 [166]3 years ago
3 0

Answer:

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

Explanation:

3A+5B → 12C

We are given with excess moles of compound B and 2 moles of compound A.

Moles of compound A = 2 moles

According to reaction, 3 moles of compound A gives 12 moles of compound C.

Then 2 moles of compound A will give:

\frac{12}{3}\times 2mol=8 mol of compound C.

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

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Answer:  The balanced equation for the given reaction is

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A chemical equation which contains same number of atoms on both reactant and product side.

For example, SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)

Here, number of atoms on reactant side are as follows.

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To balance this equation, multiply SO_{2} by 2 on reactant side and multiply SO_{3} by 2. Hence, the equation will be re-written as follows.

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Here, number of atoms on reactant side are as follows.

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Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

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