All categories

3 years ago

For the following hypothetical reaction:

Chemistry

2 answers:

ycow [4]3 years ago

8 0

For the reaction:

3A +5B--->12C

Here 3 moles of A are reacting with 5 moles of B to produce 12 moles of C.

so, 1 mole of A will produce = 12÷3 moles of C

= 4 moles of C

so 2 moles of A will produce = 4×2 moles of C

= 8 moles of C

so, 2 moles of A are reacting with excess of B to produce 8 moles of C.

so , the answer is 2 moles of A are reacting with excess of B to produce 8 moles of C.

nata0808 [166]3 years ago

3 0

Answer:

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

Explanation:

3A+5B → 12C

We are given with excess moles of compound B and 2 moles of compound A.

Moles of compound A = 2 moles

According to reaction, 3 moles of compound A gives 12 moles of compound C.

Then 2 moles of compound A will give:

$\frac{12}{3}\times 2mol=8 mol$ of compound C.

8 moles of compound C can you produce with 2 moles of compound A and excess compound B.

You might be interested in

Which member of the following pairs has the larger London dispersion forces?

Virty [35]

Answer:

H₂S; CO₂; SiH₄

Explanation:

London dispersion forces are larger in molecules that are large and have more atoms or electrons.

A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

B. CO₂ or CO

CO₂. CO₂ has more atoms. It is also linear, so the molecules can get close to each other and maximize the attractive forces.

C. CH₄ or SiH₄

CH₄. Si is below C in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

4 0

3 years ago

A mixture of nitrogen gas and oxygen gas has a total pressure of l.13 atm. If the partial pressure of oxygen is 0.43 atm, what i

Vladimir [108]

C
0.70

I hope this is help, I’m so so sorry if I’m incorrect

8 0

3 years ago

Read 2 more answers

Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc

jeka94

Answer:

$T_f$ = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

$T_i$ = 21.5°C

$C_{calorimeter}$ = 6.15 kJ/°C

$T_f$ = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate × $\frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}$

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

= 0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter = $C_{calorimeter}$ $(T_f-T_i} )$

21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

$T_f$ =25.05°C

4 0

4 years ago

Which of the following BEST supports the Big bang theory of the origin of the universe?

inysia [295]

Answer: first one

Explanation:

7 0

3 years ago

Given the balanced equation, 2 H2 + O2 -> 2 H2O, answer the following

9966 [12]

Answer: $O_2$ is the limiting reagent

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles$

$\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles$

The balanced chemical reaction is :

$2H_2+O_2\rightarrow 2H_2O$

According to stoichiometry :

1 moles of $O_2$ require = 2 moles of $H_2$

Thus 0.625 moles of $O_2$ will require= $\frac{2}{1}\times 0.625=1.25moles$ of $H_2$

Thus $O_2$ is the limiting reagent as it limits the formation of product and $H_2$ is the excess reagent as it is present more than the required amount.

8 0

3 years ago