<span>pH = pKa + log ([base]/[acid]) = -log (3.5 x 10^-4) + log (0.040/.020) = 3.46 - 0.30 = 3.16</span>
Explanation:
in it I mass=150g,initial temp 1=95,mass2=500g,temp2=?,final temperature=27.2 C1=0.444C2=4.18
using formula
m1c1(final temp-initial temp1) =m2c2(temp2-final temp)
150x0.444(27.2-95)=500x4.18(?-27.2)
66(-67.8)=2000(?-27.5)
-4474.8=2000?-55000
collect like terms
-4474.8+55000=2000?
50525=2000?
divide both sides by 2000
2000?/2000=50525/2000
initial temperature =25.26 degree Celsius
Yes they will need to worry cause the chemicals could spread in the water making it explode and kill animals and it would be very bad
Answer:
Coefficient = 1.58
Exponent = - 5
Explanation:
pH = 2.95
Molar concentration = 0.0796M
Ka = [H+]^2 / [HA]
Ka = [H+]^2 / 0.0796
Therefore ;
[H+] = 10^-2.95
[H+] = 0.0011220 = 1.122 × 10^-3
Ka = [H+] / molar concentration
Ka = [1.122 × 10^-3]^2 / 0.0796
Ka = (1.258884 × 10^-6) / 0.0796
Ka = 15.815 × 10^-6
Ka = 1.58 × 10^-5
Coefficient = 1.58
Exponent = - 5
