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Troyanec [42]
3 years ago
12

Edge2020 Need Help

Chemistry
2 answers:
Sophie [7]3 years ago
5 0

Answer: B) The fireworks give off heat

pantera1 [17]3 years ago
4 0
The answer is, the fireworks give off heat. which is exothermic
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A student analyzes soil samples from her backyard. She organizes the samples into three categories, based on their pH. The three
Bogdan [553]
Answer: circle graph.

Justification:

A circle graph (also known as pie chart) is excellent to visualize the relative size of different sectors. Being the entire circle 100%, each sector will show the percent of each category.

In the given example, the circle will be divided in 3 different sectors, in which the size is proportional to the percent of each one.

In the given case:: 

<span>pH less than 8: 20%
</span><span>
</span><span> pH between 8 and 8.5: 50%,
</span><span>
</span><span>pH greater than 8.5: 30%
</span><span>
</span><span>
</span><span>So, a sector whose area is 20% will represent the first category, a sector whose area is 50% will represent the second category, and a sector whose area is 30% will represent the third category. The whole circle is 100%, this is the sum of the 3 categories is 100%.
</span>
5 0
3 years ago
compute the mass-specific enthalpy change associated with Nz that is undergoing a change in state from 400 k to 800 k
Kitty [74]

Answer:

The correct answer is "430 kJ/kg". A further explanation is given below.

Explanation:

The given values are:

T₁ = 400 k

T₂ = 800 k

The average temperature will be:

= \frac{T_1+T_2}{2}

= \frac{400+800}{2}

= 600 \ k

From table,

At 600 k the C p will be = 1.075

Now,

⇒ The specific enthalpy = Cp(T_2-T_1)

⇒                                \Delta h=1.075 (800-700)

⇒                                      =430 \ kJ/kg

8 0
3 years ago
How many moles are in 5.30 X 1023 molecules of H2O?
arlik [135]

Answer:

0.880 (0.88039867109 to be exact)

Explanation:

To convert from molecules to moles, simply divide by Avogadro's number which is 6.02 x 10^23

So, 5.30x10^23/6.02x10^23 = 0.880

6 0
3 years ago
The enthalpy of vaporization for water is 40.67 kJ/mol and the enthalpy of fusion for water is
S_A_V [24]

Answer:

\Delta H_{dep}=-46.68kJ/mol

Explanation:

Hello!

In this case, since vaporization is the processes by which a liquid goes to the gas phase, fusion by which a solid goes to liquid and deposition by which a gas goes to solid; we infer that the following set up relates the enthalpies associated to each process:

\Delta H_{fus}+\Delta H_{vap}=-\Delta H_{dep}

Because deposition goes from a state with more energy to a state with less energy, therefore it is negative; in such a way, by plugging in we obtain:

\Delta H_{dep}=-(\Delta H_{fus}+\Delta H_{vap})\\\\\Delta H_{dep}=-(6.01kJ/mol+40.67kJ/mol)\\\\\Delta H_{dep}=-46.68kJ/mol

Best regards!

6 0
3 years ago
How would you be able to use the spectrum of each gas to establish its identity
NNADVOKAT [17]
You could compar and contrast the identities so you can compare them and identify them
3 0
3 years ago
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