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4 years ago

7

In the four-stroke internal combustion engine, fuel is ignited during the ____ stroke.

1 answer:

zzz [600]4 years ago

4 0

The power stroke, i believe.
Sorry if this does not help.

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The waste products of a nuclear fusion power plants can be best described as

I am Lyosha [343]

They can be described as small in quantity and very dangerously radioactive.

4 0

3 years ago

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Assuming that voltage remains constant, what happens to the current in a filament if it is replaced by a longer wire?

Elena L [17]

Answer:

Choice B: The current decreases.

Explanation:

The resistance of a conductor is proportional to its length when radius and resistivity stays the same. The resistance of the longer filament will be greater than the resistance of the initial one.

For Ohmic conductors,

$\displaystyle I = \frac{V}{R}$ ,

where

$I$ is the current through the conductor,
$V$ is the voltage across the conductor, and
$R$ is the resistance of the conductor.

Voltage here stays the same. Increasing the resistance $R$ of the conductor will reduce the current.

The filament might heat up over time. The filament might not be an ohmic conductor. Still, a similar trend shall exist. Resistance will be greater in the longer filament, and current will decrease.

4 0

4 years ago

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A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the

Naily [24]

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

$r = \sqrt{(3.5)^2+(2.5)^2}$

$=\sqrt{8.5}$

$SL=85$

As we know,

⇒ $SL=10 \ log(\frac{I}{I_o} )$

$85=10 \ log(\frac{I}{10^{-12}} )$

$I=3.162\times 1^{-4} \ W/m^2$

Now,

⇒ $P_{front} = I(2\pi r^2)$

$=(3.162\times 10^{-4})(2\pi\times 18.5)$

$=0.0368 \ W$

$=0.75 \ P$

or,

$=0.049 \ W$

7 0

3 years ago

A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates at 1.5m/s2? A. 51.5 N B. 4

const2013 [10]

Use the Second Law of Newton, which states that Net Force = mass times acceleration

F = m * a

F = 50 kg * 1.5 m/s^2 = 75 N

Answer: option C

3 0

3 years ago

A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a

user100 [1]

The tension in the string supporting the rod and the attached weights is 7.11 N.

<h3>Tension in the string supporting the rod</h3>

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

m1 and m2 are the two masses supported

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

Learn more about tension here: brainly.com/question/918617

#SPJ1

7 0

2 years ago