The answer might be B because the value is negative, and negative could mean slowing down.
Answer:
640 nanometer setara dengan 6.4e-7 meter
Answer:
mu = 0.56
Explanation:
The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:
![v^2=v_0^2+2ax\\](https://tex.z-dn.net/?f=v%5E2%3Dv_0%5E2%2B2ax%5C%5C)
v: final speed = 0m/s (the car stops)
v_o: initial speed in the interval of interest = 60km/h
= 60(1000m)/(3600s) = 16.66m/s
x: distance = 25m
BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:
![a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv%5E2-v_o%5E2%7D%7B2x%7D%3D%5Cfrac%7B0m%5E2%2Fs%5E2-%2816.66m%2Fs%29%5E2%7D%7B2%2825m%29%7D%3D-5.55%5Cfrac%7Bm%7D%7Bs%5E2%7D)
with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:
![F_f=ma=(1490kg)(5.55m/s^2)=8271.15N](https://tex.z-dn.net/?f=F_f%3Dma%3D%281490kg%29%285.55m%2Fs%5E2%29%3D8271.15N)
Furthermore, you use the relation between the friction force and the friction coefficient:
![F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56](https://tex.z-dn.net/?f=F_f%3D%20%5Cmu%20N%3D%5Cmu%20mg%5C%5C%5C%5C%5Cmu%3D%5Cfrac%7BF_f%7D%7Bmg%7D%3D%5Cfrac%7B8271.15N%7D%7B%281490kg%29%289.8m%2Fs%5E2%29%7D%3D0.56)
hence, the friction coefficient is 0.56
A force is a push or pull acting upon an object as a result of its interaction with another object. There are a variety of types of forces. a variety of force types were placed into two broad category headings on the basis of whether the force resulted from the contact or non-contact of the two interacting objects.
Contact Forces
Action-at-a-Distance Forces
Frictional Force
Gravitational Force
Tensional Force
Electrical Force
Normal Force
Magnetic Force
Air Resistance Force
Applied Force
Spring Force
These are types of individual forces
Applied Force
Gravitational Force
Normal Force
Frictional Force
Air Resistance Force
Tensional Force
Spring Force
2m/s
it has to be 20 charecters just ignore this your answer is up there