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Elza [17]
4 years ago
8

The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pai

r can either both act on the same body or they can act on different bodies.
a.true
b.false
Physics
1 answer:
Marrrta [24]4 years ago
6 0

Answer:

The correct answer in which peer forces each act in a different body

Explanation:

Newton's law of action and reaction states that the two forces have equal magnitude, but in the opposite direction, each acting on a body. Which creates acceleration in these, if they act in the same body it would be canceled so there would be no movement.

The correct answer in which peer forces each act in a different body

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4. A gas's solubility is best in a liquid solvent when the solution is under high or low pressure
Black_prince [1.1K]

Answer:

low pressure

Explanation:

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3 years ago
An elevator was a full mass of 2400 kg has a power rating on 16.5 horsepower how much time will it take the elevator to lift a f
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3 years ago
a cell phone uses 3.0V battery. the circuit board needs a 0.05 A current. what size resistor is needed to generate this current
san4es73 [151]

Answer:

60 Ohms

Explanation:

Ohms law states that the voltage in the circuit is directly proportional to the current through the circuit components and expressed as

V=IR

Where V is the voltage, I is current and R is resistance

Making R the subject of the formula then

R=\frac {V}{I}

Substituting 3.0V for V and 0.05 A for I then

R=\frac {3}{0.05}=60.0

Therefore, resistance is 60.0 Ohms

7 0
3 years ago
One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side
anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34  Solving for H:

H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

7 0
3 years ago
Consider two massless springs connected in parallel. Springs 1 and 2 have spring constants k1 and k2 and are connected via a thi
77julia77 [94]

Answer:

k1 + k2

Explanation:

Spring 1 has spring constant k1

Spring 2 has spring constant k2

After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.

x1 = x2

Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are

k1 = F1/x -> F1 =k1*x

k2 = F2/x -> F2 =k2*x

While F = F1 + F2

Substitute equation of F1 and F2 into the equation of sum of forces

F = F1 + F2

F = k1*x + k2*x

= x(k1 + k2)

Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)

Considering the general equation of spring forces (Hooke's Law) F = kx,

The effective spring constant for the system is k1 + k2

3 0
3 years ago
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