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Elza [17]
3 years ago
8

The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pai

r can either both act on the same body or they can act on different bodies.
a.true
b.false
Physics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

The correct answer in which peer forces each act in a different body

Explanation:

Newton's law of action and reaction states that the two forces have equal magnitude, but in the opposite direction, each acting on a body. Which creates acceleration in these, if they act in the same body it would be canceled so there would be no movement.

The correct answer in which peer forces each act in a different body

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The North American Plate is moving west at a rate of approximately 20 mm/yr. How long will it take for New York to move 10° long
scZoUnD [109]

Answer:

55000000 years

Explanation:

Rate of North American Plate moving (Velocity) = 20 mm/yr

Degrees New York has to move = 10° west

New York's longitude = 110 km/°

Distance of New York = 110×10 = 1100 km

= 1100×10⁶ mm

\text {Time taken by the continental plate}=\frac {\text {Distance of New York}}{\text {Rate of North American Plate moving (Velocity)}}\\\Rightarrow \text {Time taken by the continental plate}=\frac{1100\times 10^6}{20}\\\Rightarrow \text {Time taken by the continental plate}=55\times 10^6\ years

∴ Time taken by New York to move 10° west is 55000000 years

6 0
2 years ago
A container is filled with an ideal diatomic gas to a pressure and volume of P1 and V1, respectively. The gas is then warmed in
lilavasa [31]

Answer:

Explanation:

The  change is as follows

P₁ V₁ to 3P₁, V₁ ( constt volume )  --- first process

3P₁,V₁ to 3P₁ , 5V₁ ( constt pressure ) ---- second process

In the first process Temperature must have been increased 3 times . So if initial temperature is T₁ then final temperature will be 3 T₁

P₁V₁ = n R T₁ , n is no of moles of gas enclosed.

nRT₁ = P₁V₁

Heat added at constant volume  = n Cv ( 3T₁ - T₁)

= n x 5/3 R X 2T₁ ( for diatomic gas Cv = 5/3 R)

= 10/3 x nRT₁

= 10/3x P₁V₁

In the second process,  Temperature must have been increased 5 times . So if initial temperature is 3T₁ then final temperature will be 15 T₁

Heat added at constant pressure in second case  

= n Cp ( 15T₁ - 3T₁)

= n x 7/3 R X 12T₁ ( For diatomic gas Cp = 7/3 R)

= 28 x nRT₁

= 28 P₁V₁

6 0
3 years ago
Which statement is true about crystal lattice energy?
irinina [24]

The answer is:

It is a measure of the strength of the bonds between ions.

Lattice energy is an estimate of the strength of the bonds formed by ionic compounds.

The first two choices are wrong because it is actually the opposite.

  • As the ion size increases, lattice energy <u>decreases</u>.
  • As charge of ions increases, lattice energy <u>increases</u>

As for the other third option, it is wrong because lattice energy is the energy RELEASED not absorbed.

3 0
3 years ago
Read 2 more answers
Complete the passage.
nataly862011 [7]

Answer:

Answer: Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves.

Explanation:

There are 2 types of waves:

1. Longitudinal waves: These waves are defined as the waves in which the particles of the medium move in the direction of the wave. This requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave. This does not require a medium to travel. These can travel in vacuum also. For Example: Light waves.

Hence, Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves

8 0
2 years ago
Water flowing through a cylindrical pipe suddenly comes to a section of the pipe where the diameter decreases to 86% of its prev
masha68 [24]

Answer:

The speed in the smaller section is 43.2\,\frac{m}{s}

Explanation:

Assuming all the parts of the pipe are at the same height, we can use continuity equation for incompressible fluids:

\Delta Q=0 (1)

With Q the flux of water that is Av with A the cross section area and v the velocity, so by (1):

A_{2}v_{2}-A_{1}v_{1}=0

subscript 2 is for the smaller section and 1 for the larger section, solving for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}} (2)

The cross section areas of the pipe are:

A_{1}=\frac{\pi}{4}d_{1}^{2}

A_{2}=\frac{\pi}{4}d_{2}^{2}

but the problem states that the diameter decreases 86% so d_{2}=0.86d_{1}, using this on (2):

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\approx1.35v_{1}

v_{2}\approx(1.35)(32)\approx43.2\,\frac{m}{s}

5 0
3 years ago
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