Answer:
Vy = V0 sin 38 where Vy is the initial vertical velocity
The ball will accelerate downwards (until it lands)
Note the signs involved if Vy is positive then g must be negative
The acceleration is constant until the ball lands
t (upwards) = (0 - Vy) / -g = Vy / g final velocity = 0
t(downwards = (-Vy - 0) / -g = Vy / g final velocity = -Vy
time upwards = time downwards (conservation laws)
Answer:
The pressure of the remaining gas in the tank is 6.4 atm.
Explanation:
Given that,
Temperature T = 13+273=286 K
Pressure = 10.0 atm
We need to calculate the pressure of the remaining gas
Using equation of ideal gas
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
For a gas
![P_{1}V_{1}=nRT_{1}](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%3DnRT_%7B1%7D)
Where, P = pressure
V = volume
T = temperature
Put the value in the equation
....(I)
When the temperature of the gas is increased
Then,
....(II)
Divided equation (I) by equation (II)
![\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%7B1%7DV%7D%7BP_%7B2%7DV%7D%3D%5Cdfrac%7BnRT_%7B1%7D%7D%7B%5Cdfrac%7Bn%7D%7B2%7DRT_%7B2%7D%7D)
![\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}](https://tex.z-dn.net/?f=%5Cdfrac%7B10%5Ctimes%20V%7D%7BP_%7B2%7DV%7D%3D%5Cdfrac%7BnR%5Ctimes286%7D%7B%5Cdfrac%7Bn%7D%7B2%7DR368%7D)
![P_{2}=\dfrac{10\times368}{2\times286}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cdfrac%7B10%5Ctimes368%7D%7B2%5Ctimes286%7D)
![P_{2}= 6.433\ atm](https://tex.z-dn.net/?f=P_%7B2%7D%3D%206.433%5C%20atm)
![P_{2}=6.4\ atm](https://tex.z-dn.net/?f=P_%7B2%7D%3D6.4%5C%20atm)
Hence, The pressure of the remaining gas in the tank is 6.4 atm.
The velocity of the ball when it was caught is 12.52 m/s.
<em>"Your question is not complete it seems to be missing the following, information"</em>,
find the velocity of the ball when it was caught.
The given parameters;
maximum height above the ground reached by the ball, H = 38 m
height above the ground where the ball was caught, h = 30 m
The height traveled by the ball when it was caught is calculated as follows;
y = H - h
y = 38 - 30 = 8 m
The velocity of the ball when it was caught is calculated as;
![v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s](https://tex.z-dn.net/?f=v_f%5E2%20%3D%20v_0%20%2B%202gh%5C%5C%5C%5Cv_f%5E2%20%3D%200%20%2B%20%282%5Ctimes%209.8%20%5Ctimes%208%29%5C%5C%5C%5Cv_f%5E2%20%3D%20156.8%5C%5C%5C%5Cv_f%20%3D%20%5Csqrt%7B156.8%7D%20%5C%5C%5C%5Cv_f%20%3D%2012.52%20%5C%20m%2Fs)
Thus, the velocity of the ball when it was caught is 12.52 m/s.
Learn more here: brainly.com/question/14582703
Because the liver helps to regulate blood clotting, people<span> with liver disease (for example, hepatitis or cirrhosis) also have a tendency to </span>bleed<span> easily. Most commonly, easy or excessive bruising occurs because the skin and blood vessels are fragile.
Hope This Helped! :3</span>
In order to be considered a vector, a quantity must include Magnitude (A) and Direction (D).