3 years ago

How much concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution?

Chemistry

1 answer:

slavikrds [6]3 years ago

5 0

C₁ * V₁ = C₂ * V₂

18 * V₁ = 6.0 * 250

18 V₁ = 1500

V₁ = 1500 / 18

V₁ = 83.33 mL

hope this helps!

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