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masha68 [24]
3 years ago
6

How much concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution?

Chemistry
1 answer:
slavikrds [6]3 years ago
5 0
C₁ * V₁ = C₂ * V₂ 

18 * V₁ = 6.0 * 250

18 V₁ = 1500

V₁ = 1500 / 18

V₁ = 83.33 mL

hope this helps!


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