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masha68 [24]
3 years ago
6

How much concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution?

Chemistry
1 answer:
slavikrds [6]3 years ago
5 0
C₁ * V₁ = C₂ * V₂ 

18 * V₁ = 6.0 * 250

18 V₁ = 1500

V₁ = 1500 / 18

V₁ = 83.33 mL

hope this helps!


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An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5
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Answer:

B. 13.7 mm

Explanation:

by similarity of rectangular triangles, we have:

(1) Δ ABC and Δ AB'C'

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(2) Δ AB'C' :

∴ hypotenuse (AB')² = AC'² + B'C'²

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from (1):

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(3) in (2):

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Process

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