Ca(OH)2 -------> CaO + H2O
ratio is 1 : 1
CaO Mr= 56g
15/56 = 0.268 mol (mols of CaO in 15g)
Ca(OH)2 Mr= 74g
0.268x74= 19.83g (required amount of Cash(OH)2)
Mass of water vapor produced : 0.90 g
<h3>Further explanation</h3>
Given
0.10 g of hydrogen reacted with 0.80 g of oxygen
Required
mass of water vapor produced
Solution
Reaction
2H₂ + O ⇒ 2H₂O
If we refer to the law of conservation of mass which states that the mass before and after the reaction is the same, then the mass of water vapor formed as a product is:
mass reactants = mass products
mass of Hydrogen + mass of Oxygen = mass of water vapor
0.1 g + 0.8 g = 0.90 g
Or we can also solve<em> by using stochiometry</em> (using the concept of moles) to find the mass of water vapor
Answer: 44.8 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
To calculate the moles, we use the equation:
1 mole of 
occupies volume = 22.4L at STP
Thus 2 moles of magnesium react with=
Thus the volume of 
molecules of nitric oxide gas is 44.8 L.
It is Newtons Law Of Motion Broski....
Answer:
I am so sorry I do not know this
Explanation:
