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8090 [49]
3 years ago
9

What is conductivity? How is it measured?

Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0

<em>Conductivity is measured with a probe and a meter. </em>

Voltage is applied between two electrodes in a probe immersed in the sample water. The drop in voltage caused by the resistance of the water is used to calculate the conductivity per centimeter.

horrorfan [7]3 years ago
3 0

Conductivity is a measurement of the ability of an aqueous solution to transfer an electrical current.

Explanation:

To calculate the conductivity of a solution you simply multiply the concentration of each ion in solution by its molar conductivity and charge then add these values for all ions in solution.

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How long will it take a plane to go 800 miles if it’s traveling at an average speed of 650 miles per hour?
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If there is NO wind resistance, just plain math, this is the answer.

To get the answer you would divide 800 by 650.

800/650 = 1.230769231 (exactly)

That would translate to exactly <span>1 hour 13 minutes and 50 seconds </span>

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3 years ago
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What is a chemical entity that forms a complex ion around a central atom?
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7 0
3 years ago
If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc
Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}  

Molarity of NaOH solution = 0.1165 M

Volume of NaOH solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq    

( as acidity of NaOH is 1)

For end point:  gram equivalents of acid =  gram equivalents of base = 2.875\times 10^{-3}

Mass of acid=gram equivalents\times {\text {Equivalent mass}}

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{\text {Equivalent mass}}=83.16g

Thus equivalent mass of the acid is 83.16 grams

5 0
3 years ago
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