Answer:
The correct answer is option 2.
Explanation:
Colligative property is defined as property which depends upon only on the numbers of particles of solute dissolved in definite amount of solvent, It do not depend on the nature of the solute.
For example : NaCl solution with 0.4 molal will show same colligative properties as a that of the glucose solution with 0.04 molal concentration.
The following are the examples of colligative property:
1. Relative lowering of vapor pressure.
2. Osmotic pressure
3. Elevation in boiling points
4. Depression in freezing point
W*V i believe because it comes down to this :
I is the current, W is wattage V is volts and the * is the thing that represents the Amperes (i’m not 100% but this is my best)
The good ozone protects us from the UV/ harmful radiations whereas bad ozone is an air pollutant.
Explanation:
- There are two types of ozone layer found in the earth's atmosphere extending from troposphere to stratosphere. They are good ozone and bad ozone.
- Bad ozone as mentioned earlier it is an air pollutant and found in the ground level of earth, most accurately the troposphere. Bad ozone is formed in the ground level of earth's atmosphere by the reaction between nitrogen oxides and organic compounds which are volatile
- The Good ozone is found in the stratosphere layer of the earth's atmosphere. They protect us from harmful radiations. Good ozone layer in the stratosphere of the atmosphere is being destroyed by hydrocarbons, CFCs, and human intervention
The answer is 2 electrons I believe!
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ 
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
