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4 years ago

In a lever, the effort arm is two times as long as the load arm. The resultant force will be

1 answer:

Taya2010 [7]4 years ago

5 0

So we want to know what the resultant force would be if on the lever the effort arm is as twice as long as the load arm. So in order for the lever to be in a state of balance it must be: F1*r1=F2*r2 where F1 is the effort arm and F2 is the load arm, r1 is the perpendicular distance from the force F1 to the pivot and r2 is the perpendicular distance from the force F2 to the pivot. For both sides of the equation to be equal, since r1=2*r2, F1*2*r2=F2*r2. Now we can divide by r2 and we get: 2F1=F2. When we divide by 2: F1=(1/2)*F2. So the force of the hand that is trying to lift the load is twice as small as the force of the load we are trying to lift.

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An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elect

beks73 [17]

Answer:

Speed of the alpha particle is $v=1.8180\times 10^3m/sec$

Explanation:

We have given charge on alpha particle $q=3.2\times 10^{-19}C$

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Potential difference $V=-3.45\times 10^{-3}volt$

We have to find the speed of the alpha particle

From energy conservation we know that

$\frac{1}{2}mv^2=qV$

$\frac{1}{2}\times 6.68\times 10^{-27}\times v^2=3.2\times 10^{-19}\times 3.45\times 10^{-3}$

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3 years ago

Nresistors, each having resistance equal to 1 2, are arranged in a circuit first in series and then in parallel. What is the rat

aleksandr82 [10.1K]

Answer:

option (b)

Explanation:

Let the resistance of each resistor is R.

In series combination,

The effective resistance is Rs.

rs = r + R + R + .... + n times = NR

Let V be the source of potential difference.

Power in series

Ps = v^2 / Rs = V^2 / NR ..... (1)

In parallel combination

the effective resistance is Rp

1 / Rp = 1 / R + 1 / R + .... + N times

1 / Rp = N / R

Rp = R / N

Power is parallel

Rp = v^2 / Rp = N V^2 / R ..... (2)

Divide equation (1) by equation (2) we get

Ps / Pp = 1 / N^2

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3 years ago

When is your kinetic energy the least when swinging on a park swing?

Afina-wow [57]

Answer:

An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.

Explanation:

SO YOU HAVE THE LEAST KINETIC ENERGY AT THE HIGHEST POINT OF THE SWING WHEN IT'S NOT ACTIVE

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3 years ago

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natta225 [31]

Answer:

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Explanation:

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3 years ago

A conservative force does the same work regardless of the path taken.

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3 years ago

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