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Effectus [21]
3 years ago
9

If the mass of the egg is 60 grams (0.06 Kg), and the mass of your device is 0.5 Kg, calculate the Force of Gravity on your devi

ce with the egg included. [F = m*a, acceleration from gravity is 9.8 m/s2]
Physics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

Force of gravity is 5.488 N.

Explanation:

Given:

Mass of the egg (m) = 60 g = 0.06 kg

Mass of the device (M) = 0.5 kg

Acceleration due to gravity (g) = 9.8 m/s²

Combined mass of the egg and device is the sum of the two masses. So,

Combined mass = Mass of egg + Mass of device

Combined mass = m+M=0.06+0.05=0.56 kg

According to Newton's second law, the net force acting on a system is equal to the product of its mass and acceleration acting on it due to the force.

Here, the force is gravitational pull of Earth. So, acceleration will be acceleration due to gravity.

Therefore, the force of gravity acting on the combined mass system is given as:

F_g=(m+M)g\\\\F_g=0.56\times 9.8\\\\F_g=5.488\ N

Force of gravity is 5.488 N.

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3 years ago
A skateboarder rolls off a 2.5 m high bridge into the river. If the skateboarder was originally moving at 7.0 m/s, how much time
saul85 [17]

Answer:

  t = 0.714 s and  x = 5.0 m

Explanation:

This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed

         vₓ = 7.0 m / s

Let's find the time it takes to get to the river

         y = y₀ + v_{oy} t - ½ g t²

the initial vertical speed is zero and when it reaches the river its height is zero

        0 = y₀ + 0 - ½ g t²

        t = \sqrt{\frac{2y_o}{g}  }

        t = ra 2 2.5 / 9.8

        t = 0.714 s

the distance traveled is

       x = vₓ t

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3 years ago
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Answer:

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Objects which reflects back the sunrays could also be inserted into the sea to prevent the melting of the ice caps.

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3 years ago
The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st
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Answer:

Given:

m=1000kg

u= 16.7m/s

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Required:

s=?

Solution:

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v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

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