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pashok25 [27]
3 years ago
5

Two airplanes leave an airport at the same time. The velocity of the first airplane is 660 m/h at a heading of 28.6 ◦ . The velo

city of the second is 600 m/h at a heading of 89◦ . How far apart are they after 2.7 h? Answer in units of m.
Physics
1 answer:
Vesnalui [34]3 years ago
5 0
Can someone help me with a question? At the local ski park, James earns 519.36 for working 32 hours. Create a double number line to identify the amount of money he would make for 1, 8 and 40 hours of work?
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A group of atoms with aligned magnetic poles are known as which of the following?
cestrela7 [59]
A magnetic domain is a group of atoms aligns with magnetic poles. Domains are usually <span>light and dark stripes visible within each grain.</span>
4 0
3 years ago
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What is the smallest particle that relains<br> the properties of an element
VLD [36.1K]

Answer:

atom

Explanation:

Smallest particle of an element that identifies that element is an atom.

8 0
1 year ago
Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0
3 years ago
How much water in units of litre can fill a water tank of 1m3 capacity? Explain plx ans me
mash [69]
1000 litres of water can fill a tank of 1m3 capacity because water has a density of 1000kg/m3 and as 1 kg water = 1 liter ,
1000 liter of water can fill a tank of 1m3

5 0
3 years ago
A mobile phone is 35% efficient. Over half an hour 11 kJ of energy is transferred to the phone.
kramer
<h3><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>

  • Energy Transferre=11KJ
  • Efficiency=35%
<h3>☆Usefully transferred energy:-</h3>

\\ \sf\longmapsto 35\%\:of 11

\\ \sf\longmapsto 35\%\times 11

\\ \sf\longmapsto \dfrac{35}{100}\times 11

\\ \sf\longmapsto \dfrac{385}{100}

\\ \sf\longmapsto 3.85KJ

\\ \sf\longmapsto 3850J

6 0
3 years ago
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