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ladessa [460]
3 years ago
7

Chloe is training for her first half-marathon, which requires her to run 21.1 km. Before she runs, she carefully chooses the foo

ds that will give her the energy her body requires for the race. She stands still at the starting line, then she starts running, her body warming up as she runs. Which three energy transformations take place in this example? Potential energy to kinetic energy Chemical energy to thermal energy Chemical energy to kinetic energy Mechanical energy to chemical energy
Chemistry
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

The transformation is of chemical energy (use the ATP molecule as a resource) which is then transformed into mechanical energy (muscle contraction) and finally transformed into thermal energy (increase in body temperature, or sweating)

Explanation:

Energy is never lost, it is always transformed, that is why energy is yielding electronic movement and expressing itself in different ways, first as chemical energy, then as mechanical energy, and lastly as thermal energy.

It is important to clarify that the energy source of all this transformation is food and energy reserves.

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Please help me with this science question
elena55 [62]

Answer:

TRUE

Explanation:

The youngest rocks on the ocean floor are located at the oceanic ridge, an underwater mountain range formed from the spreading of tectonic plates

5 0
3 years ago
Read 2 more answers
Consider the reaction of glucose with oxygen: C6H12O6(s) + 6O2(g) Right arrow. 6CO2(g) + 6H2O(l)
lidiya [134]

Answer:

Subtract the sum of the heats of formation of the reactants from that of the products to determine delta H: delta H = –110.53 kJ/mol – (–285.83 kJ/mol) = 175.3 kJ.

Explanation:

Step 1: Set Up the Equation. Arrange your given ΔHf and ΔH values according to the following equation: ΔH = ΔHf (products) - ΔHf (reactants). ...

Step 2: Solve the Equation. Solve your equation for ΔHf. ...

Step 3: Validate the Sign. Adjust your ΔHf value's sign depending on whether it is for a product or a reactant.

3 0
3 years ago
Give the electron configuration of vanadium (V), atomic number 23
saveliy_v [14]

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³ or [Ar] 4s²3d³

<h3>Further explanation</h3>

Given

Vanadium, atomic number 23

Required

The electron configuration

Solution

In an atom, there are levels of energy in the shell and subshell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the subshell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The electron configuration is based on the atomic number which indicates the number of electrons of the atom

Vanadium has the atomic number 23, so the number of electrons = 23

Electron configuration:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³

or we can write it using the noble gas notation

[Ar] 4s²3d³

4 0
3 years ago
Planets in our solar system revolve around the Sun because
yulyashka [42]
Planets revolve around the sun because of gravity. When the planets were made, the sun's gravity was strong enough so that the planets continued to stay around the sun and orbit.
4 0
4 years ago
Read 2 more answers
a 0.555 g sample of mayonnase was burned in excess oxygen inside a bomb calorimeter with a total heat capacity (bomb and water)
Fofino [41]

Answer:

Dietary\ Calories=65.6kcal

Explanation:

Hello!

In this case, since we can see that the heat released by the combustion of the mayonnaise is absorbed by the bomb calorimeter and water, we can set up the following equation:

m_{mayonnaise}q_{mayonnaise}=C\Delta T

Whereas q for mayonnaise stands for the heat due to its usage; thus, we plug in to obtain:

q_{mayonnaise}=\frac{5.20kJ/\°C*2.93\°C}{0.555g} \\\\q_{mayonnaise}=27.45\frac{kJ}{g}

Now, if 10.0 g are eaten, the energy provided by it turns out:

E_{mayonnaise}=27.45kJ/g*10.0g\\\\E_{mayonnaise}=274.5kJ

And we need that value in dietary calories, 1 kcal:

Dietary\ Calories=274.52kJ*\frac{1kcal}{4.184kJ}\\\\ Dietary\ Calories=65.6kcal

Best regards!

4 0
3 years ago
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