A. Potassium oxide
B. Calcium chloride
C. Magnesium nitride
D. Sodium hypochlorite
E. Potassium nitrate
The answer to this question would be C
B is the answer , i got you
At STP (standard temperature and pressure conditions), 1 mol of any gas occupies 22.4 L
This rule is applied to O₂
22.4 L volume occupied by 1 mol
Therefore 83.4 L occupied by - 1/ 22.4 x 83.4 = 3.72 mol
stoichiometry of O₂ to H₂O is 1:2
then the number of moles of water produced - 3.72 mol x 2= 7.44 mol
mass of water produced - 7.44 mol x 18.01 g/mol = 134.1 g
correct answer is D
Answer:
Ka =
Explanation:
Initial concentration of weak acid =
pH = 6.87
HA dissociated as:
(0.00045 - x) x x
[HA] at equilibrium = (0.00045 - x) M
x =
0.000000135 <<< 0.00045