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wariber [46]
2 years ago
7

Describe the contributions of 3 scientists to our current understanding of the atom

Chemistry
1 answer:
bogdanovich [222]2 years ago
8 0

Answer:

1. Rutherford did the scattering experiment and observed that some of the rays bounce back. He concluded that there is a mass in which positive charge is concentrated. This marks the discovery of nucleus.

2. J.J Thomson discovered electrons by conducting cathode ray experiment.

3. Dalton postulated that matter is made up of small particles caled atoms

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Find the mass of an object that has a density of 1.5 g/cm3 and has a volume of 8cm3
zubka84 [21]

Answer:

density= 1.5 g/cm3

volume= 8cm 3

mass = density×volume

mass= 1.5×8

= 12 g

7 0
3 years ago
Match each type of learning to the correct definition
pishuonlain [190]

Answer:

conditioning-the process of associating a stimulus with a good or bad outcome.

trial-and-error learning-the process of performing a behavior more and more skillfully.

insight learning-the process of using prior knowledge to solve a problem.

imprinting-a bond to an indivisual or object shortly after birth or hatching.

Explanation:

Did this assignment.

3 0
2 years ago
Read 2 more answers
The image shows the representation of an unknown element in the periodic table. A square is shown. Inside the square twelve is w
avanturin [10]

Answer:

The combined mass of all the protons and electrons is 24.305.

Explanation:

From the information given about the atom, we can see that the relative atom mass of the element is 24.305.

The relative atomic mass of an atom is the combined mass of all its isotope in proportion of their geonormal abundances. On the periodic table, this mass deals with the amount of protons and neutrons present in a given atom.

7 0
3 years ago
State and explain modern periodic table. ⊕⊕
Svetradugi [14.3K]

Explanation:

the physical and chemical properties of an element are periodic functions of their atomic number.

7 0
3 years ago
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1. Compare masses: a) 0,4mol CO₂ and 0,6mol H₂O ; b) 0,135mol H₂SO₄ and 0,5mol HCI.
bixtya [17]

Answer:

you can now deduct which one is greater or smaller and by how much.

Explanation:

no of moles= mass/molar mass

1ai) 0.4 = m/ ( 12 + (16*2)

m= 0.4* 44

m= 17.6g

ii) 0.6= m/( 2*1 + 16)

m= 0.6 *18

m= 10.8g

b) 0.135 = m/ ( 2*1 +32 + (16*4)

m= 0.135* 98

m= 13.23g

ii) 0.5= m/ (1+35.5)

m= 0.5*36.5

m= 18.25g

2. Avogadro's Number = 6.02×10²³

1 mol of any element= 6.02×10²³ particles

a) 0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules

ii) 0.3 mol of CO2= (6.02×10²³) * 0.3

= 1.806 × 10²³ molecules

Ans: 0.3 mol of CO2

bi) 0.25 mol of HCl= (6.02×10²³) * 0.25

= 1.505 × 10²³ molecules

bii) - find the no of moles first:

no of moles= mass/molar mass

n= 3.4g/ 34g →mr of H2S in g=2+32= 34g

n= 0.l mol

- use the Avogadro Number.

0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules.

biii) here you're given the density, use it to find the mass of acetic acid.

ρ = 1049 g/ml

ρ = m/v, where v=5 ml

1049 = m/ 5

m= ρ*v

m= 1049*5

m= 5245 g

• convert this into moles.

mr of CH3COOH= 12 + 3+ 12+ 16+ 16+ 1

= 60

mr in g = 60g

n= m/mr

n= 5245/ 60

n= 87. 41666...

n= 87.4 moles

•using Avogadro's Number:

87.4 moles of acetic acid=(6.02×10²³)*87.4

= 2.25148* 10²⁵

= 2.25 * 10²⁵ molecules

thus, the ans for this is 5 ml of acetic acid.

7 0
2 years ago
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