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rjkz [21]
2 years ago
11

How many hydrogen molecules are there in 1 ton of hydrogen?​

Chemistry
1 answer:
zaharov [31]2 years ago
6 0
Hydrogen gas(H2) has a molar mass of 2 g. Molar mass of a substance is defined as the mass of 1 mole of that substance. And by 1 mole it is meant a collection of 6.022*10^23 particles of that substance.

So number of moles of H2 are 0.5 in this case. And thus it means there are (6.022*10^23)*0.5 particles( here they are molecules) in 1g of H2.
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If the specific heat of water is 4. 18 j/g∙°c, how much heat is required to increase the temperature of 1. 20 kg of water from 2
Mkey [24]

The heat required to increase the temperature of 1.20 g of water is  80,256 k/j

<h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

4. 18 J heat is required to change the temperature of 1.20 kg of water from 23. 00 °c to 39. 00 °c.

The heat required to raise temperature is the product of mass, specific heat and temperature change

1,200 × 4.18 × (39 − 23) = 80,256

Thus, the heat required to increase the temperature of 1.20 g of water is  80,256 k/j

Learn more about specific heat

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8 0
2 years ago
Oxygen's atomic number is 8. This means that an oxygen atom has
vladimir2022 [97]

Answer:

8 protons in its nucleus

5 0
3 years ago
Read 2 more answers
Which of the following symbols would be included in the noble gas notation for an element that had valence electrons in the 5s s
alexandr1967 [171]

Answer: C. (Xe)

Explanation:

7 0
3 years ago
Read 2 more answers
Starting with a vessel of temperature 50.1°C, a pressure of 6263.MmHg and volume 461.1mL, what is its final volume, in liters, i
il63 [147K]

Answer:

The value of final volume inside the vessel  V_{2} =  5.17 ml

Explanation:

Initial pressure P_{1} = 6263 mm Hg = 8.24 atm = 835 K pa

Initial temperature T_{1} = 50.1 ° c = 323.1 K

Initial volume V_{1} = 461.1 ml =  0.0004611 m^{3}

Final temperature T_{2} = - 95.8 ° c = 177.2 K

Finial pressure P_{2} = 411 atm = 41644.6 K PA

We know that

P_{1} \frac{V_{1} }{T_{1} }  = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation

⇒ 835 × \frac{0.0004611}{323.1} = 41644.6 × \frac{V_{2} }{177.2}

⇒ V_{2} = 5.07 × 10^{-6} m^{3}

⇒ V_{2} =  5.17 ml

This is the value of final volume inside the vessel.

8 0
3 years ago
Two students in the same class find that a piece of wood,
Naily [24]

Answer:

The wood is oak.

Explanation:

Given data:

Mass of wood = 70 g

Volume of wood = 103 cm³

Wood is oak = ?

Solution:

We will calculate the density of wood then we will compare it with literature value.

Density = mass/ volume

d = 70 g/ 103 cm³

d = 0.68 g/cm³

The density of oak is 0.59 - 0.90 g/cm³.

So its true, wood is oak.

5 0
2 years ago
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